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Alexxx [7]
2 years ago
8

Which ion in the ground state has the same electron configuration as an atom of neon in the ground state?

Chemistry
2 answers:
Ainat [17]2 years ago
6 0
  • Cl-

Lets see how

  • Z for Cl is 9
  • One electron is added so new Z=10

Electronic configuration

  • 1s²2s²2p⁶

Or

  • [Ne]

option B is correct

sleet_krkn [62]2 years ago
3 0

Answer:

Option 4, O^{2-}

Explanation:

<u>Step 1:  Determine which option is correct</u>

We know that Ne has 10 electrons therefore we need to find a different ion that has the same amount.  

Option 1 → Ca has 20 electrons and with 2+ we would remove 2 of those which would leave us with 18.

Option 2 → Cl has 17 electrons and with a - we would add 1 of those which would leave us with 18.

Option 3 → Li has 3 electrons and with a + we would remove 1 of those which would leave us with 2.

Option 4 → O has 8 electrons and with a 2- we would add 2 of those which would leave us with 10.  

Since the only one that matches up in the number of electrons is O^{2-} we can conclude that option 4 is correct.

Answer:  Option 4, O^{2-}

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A particle of mass 2.0 kg moves under the influence of the force F(x)=(-5x^2+7x)~\text{N}F(x)=(−5x ​2 ​​ +7x) N. If its speed at
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Answer:

The speed of the particle at x = 4.0 m is 13.66 m/s

Explanation:

The work done by this force between the two points above is given by

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W = [(-5x³/3) + (7x²/2)]⁴₋₄

W = [(-5(4³)/3) + (7(4²)/2)] - [(-5(-4)³)/3) + (7((-4)²)/2)] = (-50.6667) - (162.6667) = (- 213.33 J)

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K.E = mv²/2 = 2 × 20²/2 = 400 J

To obtain the kinetic energy at 4 m,

We apply the work-energy theorem which mathematically translates to

The work done in moving a particle from one point to another = Change in kinetic energy of the particle between those two points

W = ΔK.E

Work done between x = - 4m and x = 4 m is - 213.33 J

Hence, ΔK.E = -213.33 J

Change in kinetic energy of the particle between x = - 4m and x = 4m is ΔK.E

ΔK.E = (Kinetic energy at x = 4m) - (kinetic energy at x = - 4m)

- 213.33 J = (mv²/2) - 400

mv²/2 = -213.33 + 400 = 186.67 J

2v² = 2 × 186.67

v² = 186.67

v = 13.66 m/s.

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