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Bumek [7]
3 years ago
15

At what angle should you place your elbows while at your workstation? Above 120 degrees At 60 degrees Below 90 degrees Between 9

0 and 110 degrees
Engineering
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer:

Between 90 and 110 degrees

Explanation:

Ideally, the angle should not be less than 90° so that your elbows could be parallel to the workstation. This will in turn mean that the shoulders will be relaxed and it will make it a lot less stressful to keep the wrists in a straight manner.

Looking at the options, there is no exact figure of 90°, however, it could be between 90° to 110° because the difference is not going to be much in terms of making the shoulders relaxed.

Lunna [17]3 years ago
7 0

Answer:

90 degrees i did the test and i also looked it up to make sure i was right.

Explanation:

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The signal propagation time between two ground stations in a synchronous satellite link is about millisecond is​
Sonja [21]

Answer:

270 is the answer for that

6 0
3 years ago
When determining risk, it is necessary to estimate all routes of exposure in order to determine a total dose (or CDI). Recognizi
Allushta [10]

Answer:

The following are the solution to this question:

Explanation:

The Formula for calculating CDI:

\bold{CDI = \frac{C \times CR \times EF \times ED}{BW \times AT}}

_{where} \\ CDI = \text{Chronic daily Intake rate}  (\frac{mg}{kg-day})} \\\\\text{C = concentration of Toluene}\\\\\text{CR = contact rate} \frac{L}{day}\\\\\text{EF = Exposure frequency} \frac{days}{year}\\\\\text{ED = Exposure duration (in years)} = 10 \ \ years\\\\\text{BW = Body weight (kg) = 70 kg for adult}\\\\ \text{AT = average period of exposure (days) }

calculating the value of AT:

=  365 \frac{days}{year}  \times  70 \ year  \\\\ = 25550 \ days

 calculating the value of Intake based drinking:

C = 1 \ \frac{mg}{L}

CR = 2 \frac{L}{day} Considering that adult females eat 2 L of water a day,

EF = 350 \frac{days}{year} for drink

calculating the CDI value:

\to CDI = \frac{(1 \times 2 \times 350 \times 10)}{(70 \times  25550)}\\\\

             = \frac{(2 \times 3500)}{(70 \times  25550)}\\\\ = \frac{(7000)}{(70 \times  25550)}\\\\ = \frac{(100)}{(25550)}\\\\=0.00391 \frac{mg}{ kg-day}

Centered on inhalation, intake:

C = \frac{1 \mu g} { m^3} \ \ \  or \ \ \ \ 0.001  \ \ \frac{mg}{m^3}\\\\CR = 20  \frac{m^3}{day}\\\\EF = 15 \frac{min}{day}  \ \ or\ \  5475 \frac{min}{yr} \ \ \  or \ \  3.80 \frac{days}{year}\\

calculating the value of CDI:

\to CDI = \frac{(0.001 \times 20 \times 3.80 \times 10)}{(70 \times 25550)}

             = \frac{(0.76)}{(1788500)}\\\\= 4.24 \times 10^{-7} \ \ \frac{mg}{kg-day}

7 0
3 years ago
Ayuda con este problema de empuje y principio de arquimedes.
il63 [147K]

Answer:

El principio de arquimedes es un principio de la hidroestática que explica lo que experimenta un cuerpo ... la teoría y después como es costumbre pasaremos a ver problemas resueltos sobre éste principio. ... Si la magnitud del peso del cuerpo es menor a la magnitud de empuje. ... Alguien me ayuda con este Ejercicio :.

Explanation:

7 0
3 years ago
How do I find v0 using Kirchhoff's laws and Ohm's law? The answer is 25V but I'm confused about how to get that.
telo118 [61]

Answer:

  25 V

Explanation:

It is convenient to use Kirchoff's current law (KCL), which tells you the sum of currents into a node is zero. The node of interest is the top left node.

The currents into it are ...

  20 mA + (-5 -Vo)/(2kΩ) -(Vo/(5kΩ)) = 0

  20 mA -2.5 mA = Vo(1/(2kΩ) +1/(5kΩ)) . . . . add the opposite of Vo terms

  (17.5 mA)(10/7 kΩ) = Vo = 25 . . . volts . . . . divide by the coefficient of Vo

_____

You will notice that the equation resolves to what you would get if you drew the Norton equivalent of the voltage source with its 2k impedance. You have two current sources, one of +20 mA, and one of -2.5 mA supplying current to a load of 2k║5k = (10/7)kΩ. KCL tells you the total current into the node is equal to the current through that load (out of the node).

5 0
3 years ago
Why is Ethics an important part of engineering?
NemiM [27]

Answer:

Products created can change society, for better and for the worse

It was damaged in a fire

8 0
3 years ago
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