What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other
(a-2)^3+8 = a^3-8+8 = a^3
= a^3 = b^3 square root both side = a=b
<span>(b-2)^3+8 = b^3-8+8 = b^3
Thus it is 1:1.</span>
Well she charged twice as much to walk large then small. Let s be small and l be large.
We we know that
l = 2s
we also know that she wants to make 100 so
xl + ys = 100
Where where x is number of large and y is number of small. it says she walked 10 small and 5 large so
5l + 10s = 100
substitute 2s for l because they are same value as shown in first equation I made
5 (2s) + 10s = 100
10s + 10s = 100
20s = 100
s = 5
we can now solve for l
l = 2s
l = 2 * 5
l = 10
So s is 5 and l is 10.
Answer:5x7=35
8x5=40
Step-by-step explanation: well first think of what number can divide into 40 and 35 and come out as 5. So for example 35 divided 7 equals 5 and 40 divided 8 = 5 so the missing number is either 8 or 7
X + (7 + 14x) = 15x + 7
hope this helps
