Step-by-step explanation:
I am not sure what your problem here is.
you understand the inequality signs ?
anyway, to get
6×f(-2) + 3×g(1)
we can calculate every part of the expression separately, and then combine all the results into one final result.
f(-2)
we look at the definition.
into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?
is -2 < -2 ? no.
is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.
so, we have to use
1/3 x³
for x = -2 that is
1/3 × (-2)³ = 1/3 × -8 = -8/3
g(1)
again, we look at the definition.
into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?
is 1 > 2 ? no.
is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.
so we have to use
2×|x - 1| + 3
for x = 1 we get
2×0 + 3 = 3
6×f(-2) = 6 × -8/3 = 2× -8 = -16
3×g(1) = 3× 3 = 9
and so in total we get
6×f(-2) + 3×g(1) = -16 + 9 = -7
Answer:
D
Step-by-step explanation:
All real number less than 5
Part (a)
<h3>Answer: y1 and y3 are perpendicular</h3>
This is because the two slopes 2 and -1/2 multiply to -1. Perpendicular slopes multiply to -1 assuming neither line is vertical or horizontal.
=====================================================
Part (b)
Graph each line to see where they cross. The three points of intersection are
(0,4)
(2,-2)
(4,2)
The order of the points doesn't matter.
You could also form three systems of equations pairing up the equations, and solving each system. That way you can find the points of intersection. Graphing may be a better and faster route in my opinion. See the diagram below.
Answer:
1. P= 80
60/.75=80
2. x= 5/3
-27/25x / -27/25= -9/5 / -27/25
-9/5 / -27/25 --- -9/5 x -25/27
3. -300
-2.7/-2.7 = 810/-2.7
4. 120
84x100/70
<u>84/x = 70/100</u>
Answer:
(x-3) years
Step-by-step explanation:
We are given that
Age of Jonathan= x years
Sage is 7 years older than Jonathan
It means
Age of Sage=(x+7) years
We have to find the age of Sage 10 years ago.
10 Years ago,
Age of Jonathan=(x-10) years
Age of Sage=(x+7-10) years
Age of Sage=(x-3) years
Hence, 10 years ago, age of Sage =(x-3) years
