The distance between points A and C is 7 units, so to find the length we divide 35 by 7 which equals 5. Now we know that points B and D must be 5 units away from A and C, which means that B would be at (2, 3) and D would be at (2, -4). I hope this helps!
Dang that’s hard , hope somebody helps you.
Answer:
Which of the following is NOT a triangle congruence postulate or theorem?
4) none of these
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
Answer:
12th Customer
Step-by-step explanation:
We have to find the lcm (lowest common multiple) of the number.
We do that by taking their multiples. Watch down below
3 x 1 = 3 4 x 1 = 4
3 x 2 = 6 4 x 2 = 8
3 x 3 = 9 4 x 3 = 12
3 x 4 = 12
See how they both have a 12 as their first lcm.
So the 12th customer gets both items.
Glad to help!
