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sattari [20]
3 years ago
15

If the ratio of S.E to S.L is 2:5 what does the simple machine multiply

Physics
1 answer:
nignag [31]3 years ago
8 0

Answer:

hgvfvy

Explanation:

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Based on the free-body diagram, the net force acting<br> on this firework is
Strike441 [17]

0N. The net force acting on this firework is 0.

The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.

Based on the free-body diagram, we have:

The force of gases is Fgases = 9,452N

The force of the rocket Frocket = -9452

Then, the net force acting is:

Fnet = Fgases + Frocket

Fnet = 9,452N - 9,452N = 0N

4 0
3 years ago
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The Assignment: A fixed quantity of an ideal gas (R 0.28 kJ/kgK; Cv-0.71kJ/kgK) is expanded from an initial condition of 35 bar,
Nikolay [14]

Answer:

Index of expansion: 4.93

Δu = -340.8 kJ/kg

q = 232.2 kJ/kg

Explanation:

The index of expansion is the relationship of pressures:

pi/pf

The ideal gas equation:

p1*v1/T1 = p2*v2/T2

p2 = p1*v1*T2/(T2*v2)

500 C = 773 K

20 C = 293 K

p2 = 35*0.1*773/(293*1.3) = 7.1 bar

The index of expansion then is 35/7.1 = 4.93

The variation of specific internal energy is:

Δu = Cv * Δt

Δu = 0.71 * (20 - 500) = -340.8 kJ/kg

The first law of thermodynamics

q = l + Δu

The work will be the expansion work

l = p2*v2 - p1*v1

35 bar = 3500000 Pa

7.1 bar = 710000 Pa

q = p2*v2 - p1*v1 + Δu

q = 710000*1.3 - 3500000*0.1 - 340800 = 232200 J/kg = 232.2 kJ/kg

7 0
3 years ago
If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?
vampirchik [111]
Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
<span>I = 4 A</span>
8 0
3 years ago
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A 0.0600-kilogram ball traveling at 60.0 meters
Vikki [24]
     The momentum of ball is given by:

\Delta Q=mv \\ \Delta Q=6*10^{-2}*60 \\ \Delta Q=3.6kg*m/s
  
     Since both have the same momentum, we have:

\Delta Q=MV \\ 3.6=10^{-2}V \\ \boxed {V=360m/s}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.    

7 0
3 years ago
I need help on 54 plz
dalvyx [7]

Answer:

a = 2 m/s²

Explanation:

average acceleration = change of velocity / change of time

a = Δv/Δt = (20 - 10) / 5 = 10/5 = 2

3 0
3 years ago
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