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slavikrds [6]
2 years ago
10

Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in

to other types but is not itself produced?

Physics
1 answer:
labwork [276]2 years ago
4 0

Kinetic Energy

How to calculate

Kinetic energy is given by K.E.

\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2

Where

  • m is denoted to mass
  • v is denoted to velocity
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A restaurant records the number of tables served each night, and the results have the values: minimum = 3, lower quartile = 14,
dybincka [34]

To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.

<h3>How to identify the median?</h3>

In a box plot, this value is represented by a vertical line located in the middle of the graph.

<h3>How to identify the maximum and the minimum?</h3>

The maximum is the value located on the farthest right, while the minimum is located on the farthest left.

<h3>How to identify the quartiles?</h3>

Divide the graph into 4 and analyze how much each quartile represents.

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5 0
2 years ago
A 2.3 kg block of copper is heated at atmospheric pressure such that its temperature increases from 6 oC to 90 oC. How much heat
Shtirlitz [24]

Answer:

the  heat absorbed by the block of copper is 74368.476J

Explanation:

Hello!

To solve this problem use the first law of thermodynamics that states that the heat applied to a system is the difference between the initial and final energy considering that the mass and the specific heat do not change so we can infer the following equation

Q=mCp(T2-T1)

Where

Q=heat

m=mass=2.3kg

Cp=0.092 kcal/(kg C)=384.93J/kgK

T2=Final temperatura= 90C

T1= initial temperature=6 C

solving

Q=(2.3kg)(384.93\frac{J}{kgC} )(90C-6C)=74368.476J

the  heat absorbed by the block of copper is 74368.476J

7 0
3 years ago
A hollow spherical shell has mass 8.20 kg and radius 0.220 m. It is initially at rest and then rotates about a stationary axis t
Likurg_2 [28]

Answer:

8.91 J

Explanation:

mass, m = 8.20 kg

radius, r = 0.22 m

Moment of inertia of the shell, I = 2/3 mr^2

                                                    = 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2

n = 6 revolutions

Angular displacement, θ = 6 x 2 x π = 37.68 rad

angular acceleration, α = 0.890 rad/s^2

initial angular velocity, ωo = 0 rad/s

Let the final angular velocity is ω.

Use third equation of motion

ω² = ωo² + 2αθ

ω² = 0 + 2 x 0.890 x 37.68

ω = 8.2 rad/s

Kinetic energy,

K = \frac{1}{2}I\omega ^{2}

K = 0.5 x 0.265 x 8.2 x 8.2

K = 8.91 J

6 0
2 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
ratelena [41]

Answer:

a = 1.3 m/s2; fn = 63.1 n :)

8 0
2 years ago
Two moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2250 J of heat is added to the gas, and 870 J of work i
Lapatulllka [165]

Answer: The final temperature is 470K

Explanation: Using the relation;

Q= ΔU +W

Given, n = 2mol

Initial temperature T1= 345K

Heat =Q= 2250J

Workdone=W=-870J(work is done on gas)

T2 =Final temperature =?

ΔU =3/2nR(T2-T1)

ΔU=3/2 × 2 ×8.314 (T2 - 345)

ΔU=24.942(T2-345)

Therefore Q = 24.942(T2-345)+ (-870)

2250=24.942(T2-345)+ (-870)

125.09=(T2-345)

T2 =470K

Therfore the final temperature is 470K

5 0
2 years ago
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