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Mariana [72]
4 years ago
8

Which statement about elements and atoms is true?

Physics
1 answer:
Vika [28.1K]4 years ago
8 0
Atoms are the smallest unit of an element
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Why do you think aliens real? 5-8 sentence response
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Answer: I dont sorry :\.

Explanation: um hm.

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2 years ago
On July 4, 2005, the NASA spacecraft Deep Impact fired a projectile onto the surface of Comet Tempel 1. This comet is about 9.0
kenny6666 [7]

Answer:

1. M = 67,422,800,892,977.54 kg

2. r = 15 km

Explanation:

The diameter of the Comet Tempel 1, D = 9.0 km across

The speed with which the dust escapes = 1.0 m/s

1. The escape velocity, v_e, is given by the following formula

v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{R} }

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

v_e = The escape velocity of the debris = 1.0 m/s

M = The mass of the comet from where the debris escapes

From the escape velocity equation, we have;

M = \dfrac{v_e^2 \cdot R}{2 \cdot G}

Plugging in the values for the variables, we get the mass of the comet, 'M', as follows;

M = \dfrac{1.0^2 \times 9,000}{2 \cdot 6.67430 \times 10^{-11}} \approx 67,422,800,892,977.54 \, kg

The mass of the comet, M ≈ 67,422,800,892,977.54 kg

2. When the debris has lost 60% of its initial kinetic energy, we have;

60\% \, K.E. = 0.6\cdot K.E. = 0.6 \times \dfrac{1}{2} \times m \times v_e^2 = \dfrac{G \cdot M \cdot m}{r}

\therefore \, The \ distance \ of \ debris \ from \ the \ center, \,   r = \dfrac{G \cdot M }{0.6 \times \dfrac{1}{2}  \times v_e^2 }

r = \dfrac{6.67430 \times 10^{-11} \times 67,422,800,892,977.54}{0.6 \times \dfrac{1}{2} \times 1^2 } = 15,000

When the debris has lost 60% of its initial kinetic energy, the distance the debris will be from the comet's center, r = 15,000 m = 15 km

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3 years ago
1. A renewable energy source that uses the movement of air to create
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Answer:

A.wind

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solar= sun

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3 years ago
Which choice shows the size range for nanotechnology?
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What are the answer choices? Can't help till we know them!
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A loudspeaker produces sound waves that change in wavelengths from 1.0 m to 1.5 m. If the wave speed is constant,how did the vib
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The only possible explanation is that the frequency of the emitted wave has changed.
In fact, wavelength \lambda is related to the frequency f by:
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