Answer:
v = 5.75 x 10⁶ m/s
Explanation:
The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by
r = 
--------------(i)
Where,
q = charge of the particle
m = mass of the particle
Making v subject of the formula in equation (i) above gives
v = 
-------------------(ii)
Given;
r = 20cm = 0.2m
B = 0.3T
v = unknown
q = charge of proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷kg
Substitute the values of m, q, B and r into equation (ii) above to get;
v = 
Solving for v gives:
v = 5.75 x 10⁶ m/s
Therefore, the velocity of the proton is 5.75 x 10⁶ m/s
The specimen that will be on display is set up on stage. When working at greater magnifications when careful motions of the specimen slide are needed, a mechanical stage is employed.
<h3>What is a compound light microscope?</h3>
A microscope having several lenses and a separate light source is called a compound light microscope.
Ocular lenses are located in the binocular eyepieces of this type of microscope, while objective lenses are located in a rotating nosepiece that is located closer to the specimen.
Hence, the part of the compound light microscope is specimens placed for viewing is stage.
To learn more about the compound light microscope refer;
brainly.com/question/1600608
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Answer:
a) 0.0875A
b) 2.06*10^-6m/s
Explanation:
given
Diameter, d = 2.6mm = 0.0026m
Charge, Q = 420C
Time, t = 80mins = 80*60s = 4800s
Concentration of electrons, n = 5*10^28
To find the current, recall that q = it
Therefore, i = Q/t
Current, i = 420/4800
i = 0.0875A
To get the drift velocity, recall that I = n*q*Vd*A
A = πd²/4
A = π*0.0026²/4
A = 5.3*10^-6m²
Then, Vd = I/nqA
Vd = 0.0875/(5*10^28 * 1.6*10^-19 * 5.3*10^-6)
Vd = 0.0875/42400
Vd = 2.06*10^-6m/s
Note, low Vd causes low current.
Therefore, the current is 0.0875A and the Vd is 2.06*10^-6m/s
V=120 v=IR
R=2ø
I = ? I= v/r
I= 120r/ 10
Answer 12Amps
