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Elza [17]
3 years ago
10

Explain the working principle of the moving coil coil galvanometer​

Physics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

<em>When a current-carrying coil is suspended in a uniform magnetic field it is acted upon by a torque. Under the action of this torque, the coil rotates and the deflection in the coil in a moving coil galvanometer is directly proportional to the current flowing through the coil.</em>

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An object speed is 7.2 m/s and its momentum is 360 kg m/s what is mass of object
MAXImum [283]
Momentum = mass × velocity
360 = mass × 7.2
mass = 360/7.2 = 50 kg

Hope it helped!!
8 0
4 years ago
The use of a beat or a rhythm to remember something is
Mamont248 [21]
<span>The answer is Music Mnemonics. Mnemonic is originally coming from the Ancient Greek word means “memory”. It is the study and development of systems for improving and assisting the memory. Mnemonic techniques are more specific memory aids. Music Mnemonic is a way we used to remember song lyrics and rhythmic movement.</span>
5 0
3 years ago
Read 2 more answers
The graph shows the heating curve of water the X axis shows heat added overtime and Y axis shows the temperature identify the re
goblinko [34]

Answer:

liquid, solid, and gas. A heating curve shows how the temperature changes as a substance is heated up at a constant rate.

Explanation:

7 0
2 years ago
Sam, whose mass is 78 kg , stands at the top of a 11-m-high, 110-m-long snow-covered slope. His skis have a coefficient of kinet
Valentin [98]

Answer:

v = 8.09   m/s

Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

Let's calculate the energy

       

starting point. Higher

         Em₀ = U = m gh

final point. To go down the slope

         Em_f = K = ½ m v²

The work of the friction force is

         W = fr L cos 180

to find the friction force let's use Newton's second law

Axis y

        N - W_y = 0

        N = W_y

X axis

        Wₓ - fr = ma

let's use trigonometry

        sin  θ = y / L

         sin θ = 11/110 = 0.1

         θ = sin⁻¹  0.1

          θ = 5.74º

         sin 5.74 = Wₓ / W

         cos 5.74 = W_y / W

         Wₓ = W sin 5.74

         W_y = W cos 5.74

the formula for the friction force is

         fr = μ N

         fr = μ W cos θ

Work is friction force is

         W_fr = - μ W L cos θ  

Let's use the relationship of work with energy

        W + ΔU = ΔK

         -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²

        v² = - 2 μ g L cos 5.74 +2 (gh)

        v² = 2gh - 2 μ gL cos 5.74

let's calculate

        v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

        v² = 215.6 -150.16

        v = √65.44

        v = 8.09   m/s

6 0
3 years ago
A 1200-kg car initially at rest undergoes constant acceleration for 9.4 s, reaching a speed of 11 m/s. It then collides with a s
Natalka [10]

To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,

KE_i = KE_f

KE_f = \frac{1}{2} mv^2

Here,

m = Mass

V = Velocity

Replacing,

KE_f = \frac{1}{2} (12000)(11)^2

KE_f = 72600J

Therefore the  final kinetic energy of the two car system is 72.6kJ

8 0
3 years ago
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