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egoroff_w [7]
2 years ago
6

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.45 m/s in 3.02 s. Assum

ing that the player accelerates uniformly, determine the distance he runs.
Physics
1 answer:
vova2212 [387]2 years ago
8 0

Recall that average velocity <em>v</em> is given by

<em>v</em> = ∆<em>x</em>/∆<em>t</em>

where ∆<em>x</em> is displacement and ∆<em>t</em> is time.

Under constant acceleration, average velocity is also equal to the average of the initial and final velocities,

<em>v</em> = (<em>v</em>₂ + <em>v</em>₁)/2

The player starts at rest, so <em>v</em>₁ = 0, and speeds up to <em>v</em>₂ = 5.45 m/s in a matter of ∆<em>t</em> = 3.02 s. So

∆<em>x</em> = (<em>v</em>₂ + <em>v</em>₁) ∆<em>t</em> / 2

∆<em>x</em> = (5.45 m/s) * (3.02 s) / 2

∆<em>x</em> ≈ 8.23 m

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lutik1710 [3]

Coulomb's Law

Given:

F = 3.0 x 10^-3 Newton

d = 6.0 x 10^2 meters

Q1 = 3.3x 10^-8 Coulombs

k = 9.0 x 10^9 Newton*m^2/Coulombs^2

Required:

Q2 =?

Formula:

F = k • Q1 • Q2 / d²

Solution:

So, to solve for Q2

 

Q2 = F • d²/ k • Q1

Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9 Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)

Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)

Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)

Then, take the reciprocal of the denominator and start multiplying

Q2 = 1080 • 1 Coulombs/297

Q2 = 1080 Coulombs / 297

Q2 = 3.63636363636 Coulombs

Q2 = 3.64 Coulumbs

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