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egoroff_w [7]
3 years ago
6

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.45 m/s in 3.02 s. Assum

ing that the player accelerates uniformly, determine the distance he runs.
Physics
1 answer:
vova2212 [387]3 years ago
8 0

Recall that average velocity <em>v</em> is given by

<em>v</em> = ∆<em>x</em>/∆<em>t</em>

where ∆<em>x</em> is displacement and ∆<em>t</em> is time.

Under constant acceleration, average velocity is also equal to the average of the initial and final velocities,

<em>v</em> = (<em>v</em>₂ + <em>v</em>₁)/2

The player starts at rest, so <em>v</em>₁ = 0, and speeds up to <em>v</em>₂ = 5.45 m/s in a matter of ∆<em>t</em> = 3.02 s. So

∆<em>x</em> = (<em>v</em>₂ + <em>v</em>₁) ∆<em>t</em> / 2

∆<em>x</em> = (5.45 m/s) * (3.02 s) / 2

∆<em>x</em> ≈ 8.23 m

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