Describe what causes the flow of electric current. (4 points)

The charger for your electronic devices is a transformer. Suppose a 60 HzHz outlet voltage of 120 VV needs to be reduced to a de

photoshop1234 [79]

Answer:

2400 turns

Explanation:

Applying

Vs/Vp = Ns/Np.................. Equation 1

Where Vs = Secondary voltage of the transformer, Vp = Primary voltage of the transformer, Ns = number of turns in the secondary side, Np = Number of turns in the primary side.

First we make Np the subject of the equation

Np = NsVp/Vs................. Equation 2

Given: Ns = 60 turns, Vp = 120 v Vs = 3.0 V

Substitute into equation 2

Np = 60(120)/3

Np = 2400 turns

4 0

3 years ago

Would the solar panel work under a fluorescent or halogen light? explain your response being sure to relate your observations to

lina2011 [118]

A solar panel are most efficient under natural sunlight, however, a solar panel can work using artificial light simply because a solar panel collects photons which collide with silicon atoms transferring their energy which cause them to lose electrons.

3 0

3 years ago

Use a variation model to solve for the unknown value. Use as the constant of variation. The stopping distance of a car is direct

svlad2 [7]

Complete question is;

Use a variation model to solve for the unknown value.

The stopping distance of a car is directly proportional to the square of the speed of the car.

a. If a car traveling 50 mph has a stopping distance of 170 ft, find the stopping distance of a car that is traveling 70 mph.

b. If it takes 244.8 ft for a car to stop, how fast was it traveling before the brakes were applied?

Answer:

A) d = 333.2 ft

B) 60 mph

Explanation:

Let the stopping distance be d

Let the speed of the car be v

We are told that the stopping distance is directly proportional to the square of the speed of the car. Thus;

d ∝ v²

Therefore, d = kv²

Where k is constant of variation.

A) Speed is 50 mph and stopping distance of 170 ft.

v = 50 mph

d = 170 ft = 0.032197 miles

Thus,from d = kv², we have;

0.032197 = k(50²)

0.032197 = 2500k

k = 0.032197/2500

k = 0.0000128788

If the car is now travelling at 70 mph, then;

d = 0.0000128788 × 70²

d = 0.06310612 miles

Converting to ft gives;

d = 333.2 ft

B) stopping distance is now 244.8 ft

Converting to miles = 0.046363636 miles

Thus from d = kv², we have;

0.046363636 = 0.0000128788(v²)

v² = 0.046363636/0.0000128788

v² = 3599.99658

v = √3599.99658

v ≈ 60 mph

6 0

2 years ago

The expanding gases that leave the muzzle of a rifle also contribute to the recoil. A .30 caliber bullet has mass 7.20×10−3 kg a

katen-ka-za [31]

Answer:

Mg= 1.3418 kg*m/s

Explanation:

Mass of rifle

$m_{r}=2.90 kg$

Recoil velocity of rifle

$v_{r}=1.95 m/s$

Momentum of rifle

$m*v_{r}=3.0kg*1.95\frac{m}{s}==5.85 \frac{kg*m}{s}$

mass of bullet

mb=7.2x10^{-3} kg=0.0072 kg

velocity of bullet relative to muzzel

v_{b} = 601 m/s

velocity of bullet relative to earth= 601 - 1.95=599.05 m/s

momentum of bullet

$m_{b}*m_{b}=7.2x10^{-3}kg*599.05\frac{m}{s}=4.3132 \frac{kg*m}{s}$

the momentum of the propellant gases = momentum of rifle - momentum of bullet

the momentum of the propellant gases

Mg=5.655 -4.3132

Mg= 1.3418 kg*m/s

the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle is 1.3418 kgm/s

5 0

3 years ago

From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?

Radda [10]

Answer:

C. Solids,Liquids, Gases

5 0

3 years ago