I’m pretty sure it is an object with a net force of zero. All forces are balanced and EQUAL
The correct answer to this question is D
Answer:
Explanation:
Let the vertical height by which it descends be h . Let it acquire velocity of v .
1/2 mv² = mgh
v² = 2gh
As it leaves the surface of sphere , reaction force of surface R = 0 , so
centripetal force = mg cosθ where θ is the angular displacement from the vertex .
mv² / r = mg cosθ
(m/r )x 2gh = mg cosθ
2h / r = cosθ
cosθ = (r-h) / r
2h / r = r-h / r
2h = r-h
3h = r
h = r / 3
Answer:
The total volume of the air is 1000 cubic centimeters.
Explanation:
Since the bicycle pump and the bicycle tyre have the same pressure, then the total volume of the air is the sum of the volume of each element, then we translate this into the following artihmetical expression:
![V = 200\,cm^{3}+800\,cm^{3}](https://tex.z-dn.net/?f=V%20%3D%20200%5C%2Ccm%5E%7B3%7D%2B800%5C%2Ccm%5E%7B3%7D)
![V = 1000\,cm^{3}](https://tex.z-dn.net/?f=V%20%3D%201000%5C%2Ccm%5E%7B3%7D)
The total volume of the air is 1000 cubic centimeters.
Answer:2
Explanation:
Given
Velocity of bicycle is 5 m/s towards north
radius of rim ![r=20 cm](https://tex.z-dn.net/?f=r%3D20%20cm)
mass of rim ![m=2 kg](https://tex.z-dn.net/?f=m%3D2%20kg)
Angular momentum ![\vec{L}=I\cdot \vec{\omega }](https://tex.z-dn.net/?f=%5Cvec%7BL%7D%3DI%5Ccdot%20%5Cvec%7B%5Comega%20%7D)
![I=mr^2=2\times 0.2^2=0.08 kg-m^2](https://tex.z-dn.net/?f=I%3Dmr%5E2%3D2%5Ctimes%200.2%5E2%3D0.08%20kg-m%5E2)
![\omega =\frac{v}{r}=\frac{5}{0.2}=25 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7Bv%7D%7Br%7D%3D%5Cfrac%7B5%7D%7B0.2%7D%3D25%20rad%2Fs)
direction of Angular momentum will be towards west