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Bezzdna [24]
3 years ago
12

The hydra is an organism that reproduces by growing another organism from the sie of its tubular body. What type of asexual repr

oduction is this?
Chemistry
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

Explanation:

budding

Figure 13.3 (a) Hydra reproduce asexually through budding: a bud forms on the tubular body of an adult hydra, develops a mouth and tentacles, and then detaches from its parent. The new hydra is fully developed and will find its own location for attachment.

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I
Bond [772]

Answer:

about 0.7 g/mL

Explanation:

Density = mass ÷ volume

D = 5.29 g / (12.6 mL - 5.00 mL)

D = 5.29 g / 7.6 mL

D = 0.696052.... g/mL

D = about 0.7 g/mL

5 0
4 years ago
An ambulance took 2 hours to cover a distance of 10 kilometers. Find its speed.​
bekas [8.4K]

Answer:

5km/hour

Explanation:

2hours = 10km

/2              /2

1 hour = 5km

7 0
3 years ago
Read 2 more answers
What is the mass of 3.6 x 10∧24 atoms of Zinc (Zn)?
Sauron [17]
If that in the middle between the 10 and 24 is a caret, then I believe this is the work:

3.6 x 10^24 atoms Zn / 6.022x10^23 atom/mol Zn = 6 mol Zn

6 mol Zn x 65.36 g/mol Zn = 390 g Zn if you carry two significant figures with rounding at each step.

I believe that is correct as all the units cancel properly.
3 0
4 years ago
The average temperatures on the surface of five planets are given. Arrange the planets in decreasing order of their temperatures
Step2247 [10]
Where are the temperatures???

4 0
3 years ago
Read 2 more answers
Calculate the specific heat for as air if 1500.0 joules are required to raise the temperature of 50.0g from 0.0c to 40.0c
Law Incorporation [45]

The specific heat, c is 0.75 J/g°C

<u>Explanation:</u>

Heat or Energy, Q = 1500J

Mass, m = 50g

T1 =  0°C

T2 = 40°C

Specific Heat, c = ?

We know,

Q = mcΔT

Q = mc(T2-T1)

1500 = 50 X c X (40-0)

1500 = 50 X c X 40

c = 1500/ 2000

c = 0.75 J/g°C

Therefore, the specific heat, c is 0.75 J/g°C

7 0
3 years ago
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