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3 years ago

How many Magnesium are in 10MgCI2

Chemistry

2 answers:

Butoxors [25]3 years ago

7 0

Answer:

10 Mg

Explanation:

We are given the compounds MgCl₂.

For every one mole of Magnesium Chloride, there are 1 atom of Mg and 2 atoms of Cl₂.

So if we have 10 moles of MgCl₂, we will have 10 Mg.

aliina [53]3 years ago

5 0

Answer:

it is an inorganic compound consisting of one magnesium + 2 chlorides

Explanation:

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52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)

Elan Coil [88]

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂

0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:

16.0 mmol NaCl * $\frac{1mmolPb(NO_3)_2}{2mmolNaCl}$ = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

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5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

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