Happy Monday Everybody Free 100 points no joke

drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This mon

Kisachek [45]

Complete question is:

A large pool of adults earning their first drivers license includes 50% low- risk drivers, 30% moderate-risk drivers, and 20% high-risk drivers. Because these drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This month, the insurance company writes 4 new policies for adults earning their first drivers license. What is the probability that these 4 will contain at least two more high-risk drivers than low-risk drivers?

Answer:

probability that these 4 will contain at least two more high-risk drivers than low-risk drivers = 0.0488

Step-by-step explanation:

Let H represent High risk

M represent moderate risk

L represent Low risk.

The following combinations will satisfy the condition that there are at least two more high-risk drivers than low-risk drivers: HHHH, HHHL, HHHM, HHMM

The HHHH case has probability 0.2 ⁴ = 0.0016

The HHHL case has probability 4 × 0.2³ × 0.3 = 0.0096 (This is because L can be in four different places)

Similarly, the HHHM case has probability 4 × 0.2 ³ × 0.5 = 0.016

Lastly, the HHMM case has probability 6 × 0.2 ² × 0.3 ² = 0.0216 (This is because the number of ways to choose places for two M letters in this way is 6)

Summing all these probabilities, we have;

0.0016 + 0.0096 + 0.016 + 0.0216 = 0.0488

5 0

3 years ago

A rectangular box which is open at the top can be made from an12-by-18-inch piece of metal by cutting a square from each corner

algol [13]

Answer:

h=2.35in, l=13.3in and w=7.3in

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram that will represent the prolem. (Look at attached picture)

From the diagram we can see that the length ad the width of the box are found by using the following expressions:

L=18-2x

W= 12-2x

H=x

next, we can make use of the volume formula of a rectangular prism, which is the following:

V=WLH

so we can substitute the expressions we got before on the formula:

V=x(12-2x)(18-2x)

and for ease of calculation, we can multiply the terms, so we get:

$V=x(216-24x-36x+4x^{2})$

$V=x(4x^{2}-60x+216)$

$V=4x^{3}-60x^{2}+216x$

So now we can find the derivative of the volume:

$V'=12x^{2}-120x+216$

and set it equal to zero, so we get:

$12x^{2}-120x+216=0$

and now we can solve. We can start by factoring the left side of the equation, so we get:

$12(x^{2}-10x+18)=0$

which yields:

x^{2}-10x+18=0

This one can only be solved by using the quadratic formula:

$x=\frac{-b\pm \sqrt{-b^{2}-4ac}}{2a}$

so we substitute the corresponding values:

$x=\frac{-(-10)\pm \sqrt{-(-10)^{2}-4(1)(18)}}{2(1)}$

which yields:

x=7.65in or x=2.35in

we keep the 2.35in only, because the 7.65in returns an impossible box, since that would make the width a negative width.

So the 2.35in height would give us the greatest box. Now we can use it to find the height, the width and the length of the box.

Height=x=2.35

W=12-2x=12-2*2.35=7.3in

L=18-2x=18-2(2.35)=13.3in

5 0

3 years ago

Solve the system of equations using substitution: 6x – y = –15 X + 2y = 17

defon

Answer:

x = -1

y = 9

Step-by-step explanation:

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3 0

3 years ago

84 divided into sevenths added to 9 divided into thirds

mina [271]

(84÷7)+(9÷3) The parentheses are not necessary but I just put them.
I think that's what you meant. If you meant the other thing this would be the equation: (84÷7+9)÷3. Here the parentheses are nessasary

6 0

3 years ago

Read 2 more answers

7/8 5/6 which one is bigger

Novay_Z [31]

your answer is 5/6 is bigger

4 0

3 years ago

Read 2 more answers