Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:

Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,

Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.
Answer:
Undefined
Step-by-step explanation:
Its parallel to y-axis so the slope is undefined
Answer:
I think the answer is Y>-2
The total value of the sequence is mathematically given as
498501
<h3>The sum of the sequence is..?</h3>
Generally, the equation for Gauss's Problem is mathematically given as
The sum of an arithmetic series;
1+2+3+...+n= n(n+1)/2
Given an arithmetic sequence,
1+2+3+...+998,
Here,
n = 998
1+2+3+...+n=n(n+1)/2
1+2+3+...+998=98(998 + 1)/2
998 x 999 1+2+3+...+998 =2
1+2+3+...+998 = 498501
In conclusion, 498501 is the total value of the sequence.
Read more about sequence
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