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2 years ago

the actual yield of a certain reaction is 38.0 g while the theoretical yield is 50.0 g calculate the percent yield

Chemistry

1 answer:

Verizon [17]2 years ago

8 0

Answer:

76%

Explanation:

Actual yield = 38.0 g

Theoretical yield = 50.0 g

Percentage yield = ?

The relationship between these quantities is given as;

Percent yield = Actual yield / Theoretical yield * 100%

Percent yield = 38 g / 50 g * 100 %

Percent yield = 0.76 * 100 % = 76%

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suppose a student poured equal volumes of water and naoh in two different flasks. he forgets to label his flasks and is confused

ArbitrLikvidat [17]

The one with higher temperature is the one with NaOH as heatis given off during the neutralization reaction that occurs.

<h3>What is volume?</h3>

Volume can be defined as the amount of space a substance or an objects occupies usually in a closed container.

Volume is measures in litres.

When water is added to dilute acid like HCl, they become more dilute.

When NaOH is added to HCl, a neutralization reaction occurs.

The student will determine the contents of the flasks by adding 10 ml of hcl to each flask. If the NaOH reacts with the Hcl, there will be an increase in temperature.

The increase in temperature is due to the heat of neutralization of the reaction between NaOH and HCl.

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1 year ago

The solvolysis of t-butyl bromide in methanol yields 2-methylpropene in an E1 reaction (among other products). What is the effec

jolli1 [7]

Answer:

See explanation

Explanation:

For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.

The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.

Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.

Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.

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2 years ago

When aqueous solutions of calcium bromide and potassium carbonate are combined, solid calcium carbonate and a solution of potass

ladessa [460]

$K_2CO_3 + CaBr_2$ → $KBr + CaCO_3$ is the net ionic equation for this reaction.

<h3>What is an ionic equation?</h3>

An ionic equation is a synthetic equation where electrolytes are composed as separated particles.

$K_2CO_3 + CaBr_2$ → $KBr + CaCO_3$ is the net ionic equation for this reaction.

A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.

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1 year ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol