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kari74 [83]
3 years ago
13

Which set contains non-equivalent members?A) enthalpy and heat contentB) endothermic reaction and +HC) exothermic reaction and -

HD) kinetic energy and energy of motionE) high energy and high stability
Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

E

Explanation:

Here in this question, what we will do is to select which of the pairs that do not correlate.

A. Enthalpy and heat content

This two terms are at par with each other. By definition, the enthalpy of a system simply is the total amount of heat content it has.

B. Endothermic reaction and +H

These two terms are at par with each other. An endothermic reaction is one in which heat is absorbed from the surroundings. It has a positive value for the heat content i.e the enthalpy is positive and thus H is positive.

C. Exothermic reaction and -H

An exothermic reaction is one in which heat is released to the environment. It usually has a negative value for the enthalpy and thus the value of H is negative.

D. High energy and High Stability

These two terms are not at par. When an entity has or is of high energy, it is usually unstable. An entity at a higher energy level will not be stable until it goes to a lower level of energy.

Thus higher energy level is associated with lesser stability while lower energy levels are associated with higher stability. The lesser the energy of an entity, the higher its stability.

This makes the option our answer.

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A 187.4g sample of C3H5(NO3)3 decomposes to produce carbon dioxide, water, diatomic oxygen and diatomic nitrogen.
Delicious77 [7]

Answer:

See Explanation

Explanation:

The equation of the reaction is as follws;

4 C3H5(NO3)3 (l) → 12 CO2 (g) + 10 H2O (l) + 6 N2 (g) + O2 (g)

Number of moles of C3H5(NO3)3 = 187.4g /227 g/mol = 0.82555 moles

If 4 moles of C3H5(NO3)3 yields 12 moles of CO2

0.83 moles of C3H5(NO3)3 yields 0.82555 * 12/4 = 2.47665 moles of CO2

mass of CO2 produced = 2.47665 moles * 44 g/mol = 108.95 g of CO2

4 moles of C3H5(NO3)3 yields  10 moles of water

0.83 moles of C3H5(NO3)3 yields 0.82555 * 10/4 = 2.063875 moles of water

Mass of water = 2.063875 moles of water * 18 g/mol = 37.16 g

4 moles of C3H5(NO3)3 yields 1 mole of O2

0.83 moles of C3H5(NO3)3  yields 0.82555 * 1/4 = 0.2063875 moles of O2

Mass of O2 = 0.2063875 moles of O2 * 32 g/mol = 6.6 g

4 moles of C3H5(NO3)3 yields 6 moles of N2

0.83 moles of C3H5(NO3)3 yields 0.82555 * 6/4 = 1.238325 moles of N2

Mass of N2= 1.238325  moles of N2  *  28 g/mol = 34.67 g

To verify the law of conservation of mass, the total sum of mass of products must equal the sum of the mass of reactants. Thus;

108.95 g + 37.16 g +  6.6 g + 34.67 g = 187.4 g

The law of conservation of mass has been proven!

6 0
3 years ago
Un convertidor catalítico acelera la reacción del monóxido de carbono con oxígeno para producir dióxido de carbono. ¿De qué mane
vaieri [72.5K]

Answer:

a. Disminuye.

b. Disminuye.

Explanation:

¡Hola!

En este caso, considerando que tenemos una reacción en la cual se podría asumir que tanto la concentración de monóxido de carbono y la de oxígeno contribuye a la velocidad de reacción, de acuerdo a la siguiente cinética elemental:

r=k[CO]^2[O_2]

Al aplicar los siguientes cambios, resultaría:

a. En este caso, bien sabemos que la velocidad de reacción es aumentada al adicionar un catalizador ya que la constante de velocidad aumenta al disminuir la energía de activación; no obstante, al retirar el catalizador, la energía de activación aumentaría y por consiguiente la velocidad de reacción disminuiría.

b. En este caso, dado que la relación entre el oxígeno y la rapidez de reacción es directamente proporcional, es possible para nosotros determinar que al eliminar parte del oxígeno, la concentración disminuye y por ende la velocidad de reacción también.

¡Saludos!

5 0
3 years ago
Which description BEST describes a particle that contains 18 electrons, 18 neutrons and 16 protons?
Arlecino [84]

Answer:

C

Explanation:

C) an atom with an atomic number of 18

5 0
3 years ago
Which point on the number line represents -3/4​
Novosadov [1.4K]

Answer: - 0.75

Explanation:

For this question, you must remember that a fraction can be written of division.

So, -3/4 = -0.75, between -0.7 and -0.8 on the number line.

7 0
3 years ago
Read 2 more answers
If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is
Olenka [21]
K = C + 273
600 = C + 273
C = 600 - 273
C = 327C
6 0
3 years ago
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