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sweet [91]
3 years ago
14

A wire has a cross sectional area of 4.00 mm2 and is stretched by 0.100 mm by a certain force. How far will a wire of the same m

aterial and length stretch if its cross-sectional area is 8.00 mm2 and the same force is used to stretch it
Physics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer: 0.05\ mm

Explanation:

Given

Cross-sectional area of wire A_1=4\ mm^2

Extension of wire \delta l=0.1\ mm

Extension in a wire is given by

\Rightarrow \delta l=\dfrac{FL}{AE}

where, E=\text{Youngs modulus}

\Rightarrow \delta_1=\dfrac{FL}{A_1E}\quad \ldots(i)

for same force, length and material

\Rightarrow \delta_2=\dfrac{FL}{A_2E}\quad \ldots(ii)

Divide (i) and (ii)

\Rightarrow \dfrac{0.1}{\delta_2}=\dfrac{A_2}{A_1}\\\\\Rightarrow \delta_2=0.1\times \dfrac{4}{8}\\\\\Rightarrow \delta_2=0.05\ mm

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I need help pleaseee
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Answer:

8) 709.8875 J

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10) Kinetic energy increases as the object falls.

Explanation:

We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:

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h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m

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Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:

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Part 10)

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3 years ago
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A cheetah goes from 0m/s to 25m/s in 2.5 s. What is the cheetah's rate of acceleration?
RUDIKE [14]

Answer:

10 m/s²

Explanation:

Acceleration: This the rate of change of velocity. The unit of acceleration is m/s²

From the question,

a = (v-u)/t.................... Equation 1

Where a = acceleration of the cheetah, v = final velocity of the cheetah, u = initial velocity of the cheetah, t = time.

Given: u = 0 m/s, v = 25 m/s, t = 2.5 s.

Substitute these values into equation 1

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Hence the acceleration of the cheetah = 10 m/s²

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3 years ago
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