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Setler [38]
3 years ago
12

Calculate the acceleration of a car if it's velocity increases from 15 m/s to 75m/s in 5 seconds. ​

Physics
1 answer:
Andreas93 [3]3 years ago
7 0
  • initial velocity=u=15m/s
  • Final velocity=v=75m/s
  • Time=t=5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{75-15}{5}

\\ \sf\longmapsto Acceleration=\dfrac{60}{5}

\\ \sf\longmapsto Acceleration=12m/s^2

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castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

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Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

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Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

\Delta U=3.32\times10^{-3}\ J

The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

3 0
3 years ago
A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
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Answer

given,

mass of the ball = 3 kg

swing in vertical circle with radius = 2 m

   work done by the gravity = ?          

   work done by the tension = ?            

Work done by the gravity = - m g Δh            

 Δ h = 2 + 2 = 4 m                                                                

Work done by the gravity =- 3 \times 9.8 \times 4

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work done by gravity is equal to -117.6 J            

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work done by tension is equal to 0 J                          

7 0
3 years ago
Light rays travel from one medium into another and refract away from the boundary. What changes about the light to cause this re
vaieri [72.5K]

Answer:

a

Explanation:

I think its a its speed increases.....

8 0
3 years ago
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Answer:

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Explanation:

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abruzzese [7]
I'll tell you how I look at this, although I may be missing something important.

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I don't think it can be evaluated with the information given in the question.
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