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trasher [3.6K]
3 years ago
12

Yesterday, Janie walked 3

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

1 and one-fourthmiles

Step-by-step explanation:

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Darius buys a bottle of a chemical solution that contains 70% alcohol. The bottle contains 500 milliliters of solution.
Andru [333]

Answer:

350 ml

Step-by-step explanation:

70% of 500 ml = 0.7*500 ml = 350 ml

6 0
3 years ago
Read 2 more answers
Three plane tickets to New York cost $2,472.If each plane ticket costs the same amount, about how much does one ticket cost?How
Verdich [7]

Answer:  824$ for each

and will have to discount 24$ for each ticket

Step-by-step explanation:  2472/3= 824

2400/3=800

824-800=24

7 0
2 years ago
Two coins, A and B, each have a side for heads and a side for tails. When coin A is tossed, the probability it will land tails-s
BlackZzzverrR [31]

Answer:

Is the number of tosses for each coin enough for the sampling distribution of the difference in sample proportions PA-PB to be approximately normal?

b. No, 20 tosses for coin A is enough, but 20 tosses for coin B is not enough.

Step-by-step explanation:

a) Data and Calculations:

The probability of coin A landing tails-side up = 0.5

The proportion of times coin A lands tails-side up (PA) = 20 * 0.5 = 10

Therefore, the probability of coin A landing heads-side up = 0.5 (1 - 0.5)  

And the proportion of times that coin A lands heads-side up = 20 * 0.5 = 10.  

The proportion on either side is equally distributed.

This is why 20 tosses for coin A is enough, since the sample proportions PA is approximately normal, symmetric, and equally distributed.  There will be equal amounts of 10 tosses (0.5 *20) for either heads-side up or tails-side up.

For coin B, the probability of landing tails-side up = 0.8

The proportion of times coin B lands tails-side up (PB) = 20 * 0.8 = 16

Therefore, the probability of coin B landing heads-side up = 0.2 (1 - 0-.8)

The proportion on either side is not equally distributed, but skewed.

This is why 20 tosses for coin B is not enough, since the sample proportions PB is not approximately normal, symmetric, and equally distributed.  There will be 16 tosses landing tails-side up (0.8*20) and only 4 tosses landing heads-side up (0.2*20).

6 0
3 years ago
Help me answer these PLEASE ASAP
Hoochie [10]

Answer:

Answered below

Step-by-step explanation:

<u>Sheet 1: Question 3</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠LPN = ∠OPM

7 + 13x = -20 + 16x

27 = 3x

x = 9

<u>Sheet 1: Question 4</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠ABD = ∠EBC

2x + 20 = 3x + 15

-x = -5

x = 5

<u>Sheet 1: Question 5</u>

<u>Step 1: Find the value of x</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠SOP = ∠ROQ

5x = 4x + 10

x = 10

<u>Step 2: Find angles</u>

Angle SOP = 5x = 5(10) = 50°

Angle ROQ = 50° <em>(because it is vertically opposite to angle SOP)</em>

Angle SOR = 180 - 50 <em>(because all angles on a straight line are equal to 180°)</em>

Angle SOR = 130°

Angle POQ = 130° <em>(because it is vertically opposite to angle SOR)</em>

<u>Sheet 1: Question 6</u>

Angle 1 = 72° <em>(because vertically opposite angles)</em>

∠4 + ∠1 + 41 = 180° <em>(because all angles on a straight line are equal to 180°)</em>

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° <em>(because vertically opposite angles)</em>

∠2 = 67° <em>(because vertically opposite angles)</em>

<u>Sheet 2: Question 3</u>

Step 1: Find the value of x

<em>Sum of complementary angles is equal to 90°</em>

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

x = 7

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 7x + 4

7(7) + 4

Angle A = 53°

Angle B: 4x + 9

4(7) + 9

Angle B = 37°

<u>Sheet 3: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>Sum of supplementary angles is equal to 180°.</em>

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 3x - 7

3(37)-7

Angle A = 104°

Angle B: 2x + 2

2(37) + 2

Angle B = 76°

<u>Sheet 3: Question 4</u>

<em>Sum of supplementary angles is equal to 180°.</em>

<u>Step 1: Find x</u>

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

36x - 8 +12x - 40 = 180 x 4

48x - 48 = 720

48x = 768

x = 16

<em>Step 2: Find both angles with the help of x</em>

Angle 1: 1/4(36x-8)

1/4[36(16)-8] = 568/4

Angle 1 = 142°

Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

Angle 2 = 38°

<u>Sheet 4: Question 1</u>

<em>All angles on a straight line are equal to 180°</em>

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

<u>Sheet 4: Question 2</u>

Linear pair 1: 5 and 7 <em>(because both angles are on a straight line and are equal to 180°)</em>

Linear pair 2: 6 and 8<em> (because both angles are on a straight line and are equal to 180°)</em>

<u>Sheet 4: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>All angles on a straight line are equal to 180° or linear pairs are equal to 180°</em>

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

x = 150/12

x = 12.5

<em>Step 2: Find angles using the value of x</em>

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

<u>Sheet 4: Question 4</u>

<em>Linear pairs are equal to 180°.</em>

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

<em>Take LCM = 6</em>

[2(27x-6) + 3(6x-20)]/6 = 180

54x - 12 + 18x - 60 = 1080

72x - 72 = 1080

72x = 1152

x = 16

!!

7 0
3 years ago
What equation is the inverse of
ivolga24 [154]
Last option. but idk
4 0
3 years ago
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