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Alex Ar [27]
3 years ago
5

True or false please help I’ll give brainliest

Physics
2 answers:
maria [59]3 years ago
5 0

Answer:

All of them are false

Explanation:

4. electrons flow from earth to the object

5. electrons move freely

6. protons can't move

Vesnalui [34]3 years ago
3 0

Answer:

They all false

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1. Identify the significance of the following terms to the subject of the Civil War.
DanielleElmas [232]
What following terms I don’t see any please make your question clear
4 0
4 years ago
The __________ are tubular, fluid-filled structures that provide information about head rotations and movements.
shusha [124]

Answer: C

Explanation:

The semi-circular canals are tubular, fluid-filled structures that provide information about head rotations and movements.

The semi-circular canals match the description. Therefore, it is the answer.

Hope this helps!

4 0
3 years ago
Read 2 more answers
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
 The gas within a cylinder of an engine undergoes a net change in volume of 1.50 × 10-3 m3 when it does work at a constant press
Lemur [1.5K]

Answer:

work =p×v =3.27×10^5×1.5×10^-3 =490.5 joule

efficiency =w/q in

:. qin= w/efficiency =490.5/0.225=2180 joule

qout =q in - work =1689.5 joule

q out is work given as heat

4 0
4 years ago
HELP
alexdok [17]
The answer is c and my reason is I have straight As
3 0
3 years ago
Read 2 more answers
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