With velocity, you have to be careful. With velocity, it doesn't matter how much total distance you covered while you were moving. All that matters is the straight-line distance between the place you started from and the place where you stopped.
If you ended in the same place where you started from, then it doesn't matter whether you drove around town all day and then came home, or ran around laps on a circular track, or zig-zagged back and forth a hundred times. The straight distance from your start-point to your end-point is zero. So technically, according to the defintion of velocity, it was <em>ZERO</em>.
Mgh= 1/2 m v^2
gh= 1/2 v^2 9.8 * 8= 1/2 v^2
solve for v
V = sqrt(2gH)where H = 8 m.
The magnetic field lines due to a straight, current-carrying wire are circular.
<u>Explanation:</u>
The concepts of Electromagnetism brought a new revolution to the science world. The idea is the source of many new modes of power and machines that reduces the manual work. Motors are the best example of machines that run on the concepts of electromagnetism. So the concept is that a current-carrying conductor induces a magnetic field in its nearby premise.
This magnetic field can perceive by the magnetic line of forces. Now, if we pour some iron dust around a current-carrying conductor, we'll see a concentric circular pattern around the straight wire whose centre will be at the conductor axis. The pattern of these magnetic lines of force may deflect with the variation of current in the wire but remain in the circular format.
a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s
a 1.25 kilogram block is fastened to a spring with a 17.0 newtons per meter spring constant. Given that K is equal to 14 Newtons per meter and mass equals 10.5 kg. The block is then struck with a hammer by a student while it is at rest, giving it a speedo of 46.0 cm for a brief period of time. The required energy provided by the hammer, which is half mv squared, is transformed into potential energy as a result of the succeeding oscillations. This is because we know that energy is still available for consultation. So access the amplitude here from here. He will therefore be equal to and by. Consequently, the Newton's spring constant is 14 and the value is 10.5. The velocity multiplied by 0.49
Speed at X equals 0.35 into amplitude, or vice versa. At this point, the spirit will equal half of K X 1 squared plus half. Due to the fact that this is the overall energy, square is equivalent to half of a K square or an angry square. amplitude is 13 and half case 14 x one is 0.35. calculate that is equal to initial velocities of 49 squares and masses of 10.5. This will be divided in half and start at about 10.5 into the 49-square-minus-14. 13.42 into the entire square in 20.35. dividing by 10.5 and taking the square as a result. 231 6.9 Six centimeters per square second. 10.5 into 49 sq. 14. 2 into a 13.42 square entire. then subtract 10.5 from the result to get the square. So that is 48.13cm/s.
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This is incomplete question Complete Question is:
a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?
