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2 years ago

8

A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti

me, at which rate is the diver accelerating ?

2 answers:

Sergeeva-Olga [200]2 years ago

8 0

Acceleration = (change in speed) / (time for the change)

   =    (49 m/s) / (5 seconds)

   = (49 / 5) m/s / s

   =    9.8 m/s²

mihalych1998 [28]2 years ago

3 0

Your answer would be 9.8

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