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solmaris [256]
3 years ago
8

A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti

me, at which rate is the diver accelerating ?
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

                       =       (49 / 5)  m/s  /  s

                       =            9.8 m/s² 
mihalych1998 [28]3 years ago
3 0
Your answer would be 9.8
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Answer:

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Explanation:

Let the momentum of the two balls be A and B respectively.

Momentum A = 16 kgm/s

Momentum B = 0 kgm/s (since the ball is at rest).

Total momentum = A + B

Total momentum = 16 + 0

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Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

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6 0
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lidiya [134]
Divide 24 by 12.
24/t = 12
24/12 = t
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6 0
3 years ago
Can someone help me on no. 6
liq [111]

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Answer:

2090 J

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