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3 years ago

Question 3 (1 point)

Physics

1 answer:

ASHA 777 [7]3 years ago

7 0

Answer:

twice as much work

Explanation:

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A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo

Svetllana [295]

Answer:

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

Explanation:

We can find the gravitational potential energy using the following formula.

$GPE=mgh$

Identifying given information.

The nickel has a mass $m=0.005 \,kg$ , and it is a the top of Washington Monument.

The Washington Monument has a height of $h=555 \, ft$ , thus we need to find the equivalence in meters using unit conversion in order to find the gravitational potential energy.

Converting from feet to meters.

Using the conversion factor 1 m = 3.28 ft, we have

$h = 555 \, ft \times \cfrac{1 \, m}{3.28 \, ft}$

That give u s

$h = 169.2 \, m$

Finding Gravitational Potential Energy.

We can replace the height and mass on the formula

$GPE=mgh$

And we get

$GPE=(0.005)(9.8)(169.2) \, J$

$\boxed{GPE=8.29 \,J}$

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

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3 years ago

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Your soccer team needs to add a new player midseason. Which of these people would most likely demonstrate good sportsmanship bas

Irina18 [472]

Jasper, because he developed friendships playing with everyone last year,

Thats the answer

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3 years ago

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Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed of a

Pie

Answer:

Part a)

$v = 7407.1 m/s$

Part b)

$v_{rel} = 1.05 \times 10^4 m/s$

Explanation:

Part a)

As we know that orbital velocity at certain height from the surface of Earth is given as

$v = \sqrt{\frac{GM}{R+h}}$

here we know that

$M = 5.98 \times 10^{24} kg$

$R = 6.37 \times 10^6 m$

$h = 900 km = 9.0 \times 10^5 m$

now we have

$v = \sqrt{\frac{(6.67 \times 10^{-11})(5.98 \times 10^{24})}{6.37 \times 10^6 + 9.0 \times 10^5}}$

$v = 7407.1 m/s$

Part b)

When a loose rivet is moving in same orbit but at 90 degree with the previous orbit path then in that case the relative speed of the rivet with respect to the satellite is given as

$v_{rel} = \sqrt{2} v$