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tatiyna
2 years ago
12

CAN SOMEONE PLEASE HEALP MEEEEEEE A rectangle has an area of 24 square units and a side length of 2 3/4 units. Find the other si

de length of the rectangle.
Mathematics
1 answer:
Trava [24]2 years ago
3 0

Answer:

12

Step-by-step explanation:

Using the formula

A=wl

Solving for l

1=a/w=24/2=12

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A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
3 years ago
It takes teccance 5 minutes to read 1 pages. Of terrance read for about an hour estimate how many pages he should read
Semenov [28]

Answer:

12

Step-by-step explanation:

That’s what I got

6 0
2 years ago
Read 2 more answers
Can someone help please!!!!!!!!!!!!!!
Ksenya-84 [330]

Step-by-step explanation:

The population of a small town is 1600 and is increasing at a rate or. 3% per year.

8 0
2 years ago
John’s teacher gave him the following system of equations and asked him to find the point of intersection. 3x + 2 = y 2x – 3= y
Galina-37 [17]

1) to this case you must match both equations

3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5

now the value of x  substitute it in the any of two equations, y = 3(-5)+2 = -13

and the other equation is the same value

y = 2(-5)-3 = -13

the point is ( -5,-13)

7 0
3 years ago
This is really important i have to get this one tomorrow please help me
Murrr4er [49]
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3 years ago
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