The line containing the vector <em>q</em> can be obtained by scaling <em>q</em> by an arbitrary scalar <em>t</em>. To make this line pass through the point <em>p</em>, translate this line by a vector <em>p</em> pointing from the origin to <em>p</em>.
So the line we want has equation
<em>r</em>(<em>t</em>) = <em>q</em><em>t</em> + <em>p</em> = (14, -8)<em>t</em> + (-4, 12) = (14<em>t</em> - 4, 12-8<em>t</em>)
where <em>t</em> is any real number.
We have been given that the legs on a right triangle are 15.25 inches and 14.1 inches. We are asked to find the hypotenuse of the right triangle.
We will use Pythagoras theorem to solve our given problem.
Now we will take positive square root on both sides.
Upon rounding to nearest hundredth, we will get:
Therefore, the length of the hypotenuse is approximately 20.77 inches.
Answer:
y - 6 = 2/3( x + 1)
Step-by-step explanation:
Equation for point slope form
y - y1 = m( x - x1)
( x1 , y1) - point on the line
m - slope of the line
Given
Slope: 2/3
Point ( -1 , 6)
x1 = -1
y1 = 6
m = 2/3
Substitute the value into the equation
y - 6 = 2/3(x - (-1)
y - 6 = 2/3( x + 1)
The equation of the line in point slope form is
y - 6 = 2/3( x + 1)
The answer is a. 145° because a line will always equal 180° so just subtract 180-35 and you get 145°! hope this helped :)
Answer:
3.576 cm
Step-by-step explanation:
radius of ball, r=?
Given:
Density, p = 0.600g/mL
mass, m= 115g
finding volume, v of ball by using formula p=m/v
v= m/p
= 115/0.600
=191.666 mL^3
=191.666 cm^3
Now using formula v= (4/3)πr^3 to find radius, r of the ball
r^3= 3v/4π
= 3(191.666)/4π
=45.75 cm
r =3.5767 cm !
