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Yuki888 [10]
3 years ago
10

NEED HELP ASAP NO LINKS AND NO JUST SAYING HI, PLEASE ANSWER LEGITIMATELY! THANK YOU!!!! <3

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

x=42.5

Step-by-step explanation:

First, start by setting up the equation

these are both same side interior angles, so they both add up to 180

(3x+10) + x = 180

4x+10 =180

subtract both sides by 10

    -10    -10

4x=170

divide both sides by 4

x=42.5

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Which of the following expressions are equivalent to -8/11-3/4-1/4 (choose three answers ​
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Answer:

This is the answer: choose

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5 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
What's the answer to this?? I've tried 10 times and I can't solve it. Please help me!!
Lera25 [3.4K]

Answer:

whats the question

Step-by-step explanation:

4 0
3 years ago
ANT
ExtremeBDS [4]

Answer:

Algebra Examples

Popular Problems Algebra Find the Axis of Symmetry f(x)=x^2-5 f(x)=x2−5 Set the polynomial equal to y to find the properties of the parabola. y=x2−5

Rewrite the equation in vertex form.

y=(x+0)2−5 Use the vertex form,  y=a(x−h)2+k, to determine the values of a, h, and k.a=1h=0k=−5

Since the value of a is positive, the parabola opens up.

Opens Up

Find the vertex

(h,k).(0,−5)

Find p, the distance from the vertex to the focus.

14 Find the focus.

(0,−194)

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

x=0

3 0
3 years ago
What is the answer for <br><br><br> -|-10| + (-3) + |5|
Nuetrik [128]

Your answer would be -8

7 0
3 years ago
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