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Soloha48 [4]
3 years ago
12

What is lenth of EF​

Mathematics
2 answers:
butalik [34]3 years ago
6 0

Answer:

6 Because if you count the squares Im not 100% sure

Step-by-step explanation:

It is also positive

oee [108]3 years ago
6 0

Answer:

\sqrt{58}

Step-by-step explanation:

EF =  \sqrt{ {3}^{2} +  {7}^{2}  }  =  \sqrt{9 + 49}  =  \sqrt{58}

If they want a decimal answer just type √(58) in a calculator.

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Grace is measured for her annual check up. She is inches tall. Last year she was inches tall. How much did she grow in one year?
Ne4ueva [31]
You didn't include the actual number in inches.
5 0
4 years ago
Point F is on circle C. What is the length of line segment GF?
Levart [38]
The answer:
the full question is as follow:
<span>Point F is on circle C. What is the length of line segment GF?

12.5  units
15.0  units
17.5  units
20.0  units

according to the image, GF= GC + CF

CF is the radius of the circle, so it is CF =CE = 7.5
all that we want to find is the value of GC
let's consider the triangle GEC. This is a right triangle, so for finding GC, we can apply Pythagorean theorem

that is, GE² + EC² = GC², and from this, we have GC = sqrt(</span>GE² + EC² )

GC = sqrt(10² + 7.5² )=sqrt(56.25)=12.5
<span>
therefore, </span>GF= GC + CF=12.5 + 7.5 = 20.0
the answer is 20.0  units

8 0
3 years ago
Read 2 more answers
What is b plus 14 written a expression
Romashka-Z-Leto [24]
Answer: b+14
Hope it helps :)
6 0
3 years ago
Carla is renting a canoe. It’s cost $80 for 2 hours and $160 for 4 hours. What is the rate per hour?
patriot [66]
<span>Carla is renting a canoe. It’s cost $80 for 2 hours and $160 for 4 hours. What is the rate per hour?

If we want to get a full understanding of this question we must use the information given.

If renting the canoe cost $80 per 2 hours, to get 1 hour we must divide $80 by 2.

</span>\frac{80}{2}=40

or $40

We can also use $160 and 4 hours

\frac{160}{4}=40

or $40

So the rate per hour is $40

8 0
4 years ago
Read 2 more answers
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\&#10;\Rightarrow \cos 2A (\cos^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ &#10;\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) &#10;

go to right side now

4( \cos^6 A - \sin^6 A)\\&#10;\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\&#10; \Rightarrow Left hand side
4 0
3 years ago
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