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marin [14]
2 years ago
10

Help plssss I will do anythinv

Mathematics
1 answer:
Stels [109]2 years ago
4 0
The answer is 3 feet 7 inches
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Evquivilent Ratio for 23:37
solong [7]

Answer:

46:74

Step-by-step explanation:

7 0
3 years ago
Simplify 4radical2plus7radical2minus3radical2
zlopas [31]
Let "radical 2" be represented by "r."

Then you are to simplify 4r + 7r - 3r.  This comes out to 11r - 3r = 8r.

The answer is 8 radical 2.


3 0
3 years ago
√180 can be expressed in the form p√q. where p and q are integers. Find the smallest value of p + q. ​
frutty [35]

Answer:  

The smallest value of p+q is 11

It happens when p = 6 and q = 5.

=======================================================

Explanation:

Let's factor 180 in such a way that exactly one factor is a perfect square.

I'll ignore the trivial factor of 1.

Here are the possible factorizations we could go with:

180 = 4*45

180 = 9*20

180 = 36*5

Those factorizations then lead to the following

\sqrt{180} = \sqrt{4*45} = \sqrt{4}*\sqrt{45}= 2\sqrt{45}\\\\\sqrt{180} = \sqrt{9*20} = \sqrt{9}*\sqrt{20}= 3\sqrt{20}\\\\\sqrt{180} = \sqrt{36*5} = \sqrt{36}*\sqrt{5}= 6\sqrt{5}\\\\

Then we have

p+q = 2+45 = 47

p+q = 3+20 = 23

p+q = 6+5 = 11

The smallest value of p+q is 11 and it happens when p = 6 and q = 5.

Side note: p+q is smallest when we go with the largest perfect square factor.

6 0
1 year ago
F r e e points!!!!!!!!!!!!!!!!!
inn [45]

Answer:

gang

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
(30 points)
Pani-rosa [81]

The vertices of the triangle are the points where any pair of lines intersect.

We start by setting up the system

\begin{cases}y=-x+2\\y=2x-1 \end{cases} \iff -x+2=2x-1 \iff 3x=3 \iff x=1

Using one of the two equations we can derive the correspondent y value:

f(x)=-x+2 \implies f(1)=-1+2 = 1

So, one vertex is (1, 1)

We choose the other two pairs of lines to find the other vertices:

\begin{cases}y=-x+2\\y=x-2 \end{cases} \iff -x+2=x-2 \iff x=2 \implies y = 0

\begin{cases}y=x-2\\y=2x-1 \end{cases} \iff x-2=2x-1 \iff x=-1 \implies y=-3

So, the three vertices are (1, 1), (2, 0), (-1, -3).

8 0
3 years ago
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