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Andreyy89
3 years ago
6

If AABC ~ AEDC, find the value of x. a. 32 5.8 C. 40 d. 15

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

x = 15

Step-by-step explanation:

If ABC similar to EDC then we can use the similarity ratio to find the value of x

32/(3x-5) = 56/(5x-5) cross multiply the fractions

160x - 160 = 168x - 280 export like terms to the same side of the equation

280 - 160 = 168x - 160x

120 = 8x divide both sides by 8

15 = x

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0.12x - 1.5= 0.24x - 0.06
Sophie [7]

To solve this equation, lets move all of the variables to one side of the equation and the constants to the other.

0.12x - 1.5 = 0.24x - 0.06

Subtract 0.12x from both sides of the equation

-1.5 = 0.12x - 0.06

Add 0.06 to both sides of the equation

-1.44 = 0.12x

Divide both sides by 0.12 to isolate x

x = -12

5 0
3 years ago
If the radius of a circle is 5 inches, what is the diameter of that circle? Show
vodomira [7]

Answer:

If the radius of a circle is 5 inches, the diameter is 10.

Step-by-step explanation:

This is because to find the diameter of a circle sing the radius is to multiply it by two. 5x2=10

So the diameter is 10. If you want to find the radius just reciprocate the process, divide the diameter by 2 and yo will get the radius.

I really hope this helped you out. Make sure to give my answer brainliest. Have a radiant day or night ! :D

6 0
3 years ago
What is the number????
Dafna1 [17]

Step-by-step explanation:

n-a\ number\\\\3.145

8 0
3 years ago
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

7 0
3 years ago
Collins is working.......
lesya [120]
Let n represent the amount Colin earned on Sunday.

On Sat. he earned n/2; on Sun. he earned n; and on Friday he earned (1/2)(n/2).

Then n/2  +  n  + n/4 = $70

Mult. all terms by 4 to eliminate fractions:

2n + 4n + n = $280

7n = $280  =>  n = $40

Colin earned n/2, or $20, on Saturday; n, or $40, on Sunday; and n/4, or $10, on Friday.

Note that $20 and $40 and $10 add up to $70, as they must.
4 0
4 years ago
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