Answer:
10a+b+9c
Step-by-step explanation:
first you have to join the like terms then you add them then you write the answer, I hope you understood
9c+5a+5a+b
9c+10a+b
10a+b+9c
Answer:
Step-by-step explanation:
Even though you didn't provide options from which to choose, you don't need them to figure out the system. We need an equation that involves the NUMBER of people and then we need an equation that involves the MONEY earned. Two different things here.
As for the number of people, we know that the number of adult tickets + the number of children = 12 people, so
x + y = 12.
That's the first equation. Now for the money:
21.50x + 14.75y = 204.00
That's your system.
Answer:
In the long run, ou expect to lose $4 per game
Step-by-step explanation:
Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.
Assuming X be the toss on which the first head appears.
then the geometric distribution of X is:
X
geom(p = 1/2)
the probability function P can be computed as:

where
n = 1,2,3 ...
If I agree to pay you $n^2 if heads comes up first on the nth toss.
this implies that , you need to be paid 

![\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20%5E%7Bn%7D_%7Bi%3D1%7D%20n%5E2%20P%28X%3Dn%29%20%3DVar%20%28X%29%20%2B%20%5BE%28X%29%5D%5E2)
∵ X
geom(p = 1/2)








Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6
= $4
∴
In the long run, you expect to lose $4 per game