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nignag [31]
3 years ago
12

Can anyone please help me with this math equation?

Mathematics
1 answer:
brilliants [131]3 years ago
5 0

Answer:

1/5

Step-by-step explanation:

umm what's (3/5)/3

1/5

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X^2+10x+19=0 complete the square PLEASE EXPLAIN
wlad13 [49]

Answer:

Step-by-step explanation

In the form ax^2+bx+c

a x c should equal two factors of b

However, in this equation

1 x 19 has no factors that = 10

so you must use the Quadratic Formula which is,

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}

so the answer should be

x = \frac{-10+-\sqrt{10^2-4(1)(19)} }{2(1)}

x = \frac{-10+-\sqrt{24} }{2}

x = \frac{-10+2\sqrt{6} }{2}      and    x = \frac{-10-2\sqrt{6} }{2}

8 0
2 years ago
80% of what number is 190
Degger [83]
80% of 190 = 152
THE ANSWER IS 152
6 0
2 years ago
Read 2 more answers
What the answer please help marking brainliest if it's correct and explain​
kolezko [41]

Answer: The answer is C or Median

Step-by-step explanation:

8 0
3 years ago
A national military bureau for a certain country collects data on active members in the military. Results are published in a nat
Artemon [7]

Answer:

9.193259%

Step-by-step explanation:

In order to obtain the percentage of military members in the reserves who are​ Black, we will have to multiply the percentage of Black military members in the reserve by the percentage of military members in the reserve. This is calculated as follows:

Military members in the reserves who are​ Black (%) = 77.1771​% × 11.9119​%

                                                                                      = 9.193259%

Therefore, he percentage of military members in the reserves who are​ Black is 9.193259% .

Example

For example, let assume the total number of active members in the military is 100.

To obtain the number of military members who are in the reserves, we multiply 77.1771​% by 100. This gives us 78 approximately.

To obtain the number of military members in the reserves who are​ Black, we multiply 11.9119​% by 78 we got above who are active military members in the reserves. This gives us 9 members approximately.

I wish you the best.

3 0
3 years ago
Read 2 more answers
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
3 years ago
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