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3 years ago

The question is given in the picture below.... please help me and mention all the steps..

Physics

1 answer:

I am Lyosha [343]3 years ago

8 0

Answer:

a)water is turning into ice it is changing it's state from liquid to solid

b)B to C ice is melting and it is changing it's state from solid to liquid

C to D water is boiling and it is changing it's state from liquid to vapours(steam)

c) temperature

At A 0

At B 0

At C 100

At D 100

Explanation: The temperature will remain 0 degrees Celsius until all the ice becomes water and the temperature will remain 100 degrees Celsius until all the water changes into steam.

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Describe the magnetic field lines around a bar magnet

Sophie [7]

The lines can be traced out with a compass. The needle is like a permanent magnet and the north indicator is the north end of a magnet.

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3 years ago

Read 2 more answers

What is the acceleration of the motorcycle in section CD?

jenyasd209 [6]

Answer:

30m/s²

Explanation:

The acceleration of the motorcycle in section CD is the slope of the velocity - time graph.

Given that;

Initial velocity = 20m/s Time = 6s

Final velocity = 50m/s Time = 7s

The time interval = 7s - 6s = 1s

So;

Acceleration = $\frac{Change in velocity }{time}$ = $\frac{50 - 20}{1}$ = 30m/s²

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3 years ago

A particle moves with acceleration function a(t) = 5 + 4t - 2t^2. Its initial velocity v(0) = 3 m/s and its initial displacement

eimsori [14]

Answer:

Its position after 4 seconds is 62 meters.

Explanation:

It is given that,

The acceleration of the particle is given by equation :

$a(t)=5+4t-2t^2$

Also, $a=\dfrac{dv}{dt}$

$v=\int\limits {a.dt}$

$v=\int\limits {(5+4t-2t^2).dt}$

$v=5t+2t^2-\dfrac{2}{3}t^3+c$

At t = 0, $v(0)=3\ m/s$ . So, c = 3

$v=5t+2t^2-\dfrac{2}{3}t^3+3$

Also, $v=\dfrac{ds}{dt}$ , s is the position

$s=\int\limits {v.dt}$

$s=\int\limits {(5t+2t^2-\dfrac{2}{3}t^3+3).dt}$

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+c'$

At t = 0, $s(0)=10\ m$ . So, c' = 10

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+10$

At t = 4 s

$s=\dfrac{5}{2}(4)^2+\dfrac{2}{3}(4)^3-\dfrac{(4)^4}{6}+3(4)+10$

s = 62 m

So, at t = 4 seconds the position of the particle is 62 meters. Hence, this is the required solution.

5 0

3 years ago

Calculate the weight of an object that has a mass of 100 kg on earth

finlep [7]

Answer:

W = 980 N

Explanation:

Weight = Mass x Gravity

Weight = (100kg) x (9.8 $\frac{m}{s^2}$ )

Weight = 980 N

7 0

3 years ago

. In a solid, particles do not move around each

nordsb [41]

Answer:

I am sure the awnser to this is

B. vibrate

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3 years ago

The question is given in the picture below.... please help me and mention all the steps..​

The question is given in the picture below.... please help me and mention all the steps..