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o-na [289]
4 years ago
6

Identify a situation in which you would want to have a high

Physics
2 answers:
Andreyy894 years ago
7 0

Answer: A voltmeter must have a high resistance where as an ammeter must have a low resistance.

Explanation:

A voltmeter is a device which is connected in parallel to the component across which voltage needs to be measured. In a parallel circuit voltage drop is same at the nodes. The parallel connection must not offer easier path for current to divert from the main circuit and travel. Thus, a voltmeter must have high resistance.

On the other hand, an ammeter which is used to measure current in the circuit must have low resistance as it is connected in series. It should not offer resistance as it would reduce the actual current and measurement would be inaccurate.

Allushta [10]4 years ago
7 0
Higher resistance - on heater (need water temperature ASAP)
Lower resistance  - any electricity wire on the street (energy supply to the households, not to loose much on the way)
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Vadim26 [7]

Answer:

The velocity of the camera is 33.11 m/s.

Explanation:

Given that,

Speed = 10.8 m/s

Altitude = 50 m

Suppose determine the velocity of the camera just before it hits the ground?

We need to calculate the velocity of the camera

Using equation of motion

v^2=u^2+2gs

Where, v = final velocity of camera

u = initial speed of camera

s = distance

Put the value into the formula

v^2=(-10.8)^2+2\times(-9.8)\times(-50)

v=\sqrt{1096.64}

v=33.11\ m/s

The direction will be downward so it is the negative velocity.

Hence, The velocity of the camera is 33.11 m/s.

8 0
3 years ago
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sammy [17]
I think it’s the Full Moon
4 0
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A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​
lidiya [134]

Answer:

40,000N

Explanation:

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4 0
3 years ago
What is milo Murphy’s law
yKpoI14uk [10]

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3 years ago
Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

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C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

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E = \frac{V}{d}

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E   = 5291.00 V/m

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5 0
3 years ago
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