Classify the shape as precisely as possible based on its markings.

Show that parallelogram with its diagonals intersecting at 90° is rhombus.

34kurt

I do not have an answer for that, but you should try looking for that on google or yahoo answers.

8 0

3 years ago

Chapter 4: Explain how you can

xxTIMURxx [149]

x-intercept(s):

( 7 , 0 ) , (-1,0)

y-intercept(s):

(0,-7)

Step-by-step explanation:

3 0

2 years ago

Christie needs 54.3 Square feet of laminate wood suppose each square foot of laminated wood cost $.60 find the amount she has to

Irina18 [472]

It will cost $33.

Since wood cost $ .60 sq ft, you can assume she needs to buy 55 sq ft because she will need to buy enough to have 54.3 square ft.

55 x $ .60 = $33

$32.58 would be he total for the 54.3 sq ft and .42 cents would be for the left over .7 sq ft that she didn’t use

7 0

2 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago

The original price of a bicycle was marked down $20 to a sale price of $85. What was the original price ⁉️

vovikov84 [41]

The price was marked down. If the price was reduced, we have to sum with the other value to find the original price:

$85 + 20 = \boxed {105}$

The original price was $105.

4 0

3 years ago