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3 years ago

A geometry fact that I find helpful. (Brainly, please don't take this down it is very educational)

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

thx

sergeinik [125]3 years ago

5 0

Answer:

Thank you so much for this

Step-by-step explanation:

Have a nice day ! :)

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If Bob mowed 14x² + 12x – 3 yards total for the entire week, how many yards

navik [9.2K]

Answer:

I am going with zero yards.

Step-by-step explanation:

If Bob mowed 14x² + 12x – 3 yards total for the entire week, how many yards

did he mow during the rest of the week?

If he mowed 14x² + 12x – 3 yards for the entire 7 days of the week. He would not have anymore days to left in the week to mow, so he mowed ZERO more yards

8 0

3 years ago

Given the recursive formula for an arithmetic sequence find the common difference and the 52nd term

Mice21 [21]

Answer:

Common difference(d) $a_{52}$

(21) -10 -548

(22) -7 -323

(23) 10 547

(24) -100 -5118

Step-by-step explanation:

Let the common difference be denoted by 'd'.

Also the nth difference of an arithmetic sequence is given by: $a_{n}=a_{1}+(n-1)\times d$

(21)

We are given a recursive formula as:

$a_{n}=a_{n-1}-10$

The first term is given by:

$a_{1}=-38$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-10$

The nth term of an arithmetic sequence is given by:

$a_{n}=a_{1}+(n-1)\times d$

Here $a_{1}=-38$ and $d=-10$ .

Hence, $a_{52}=-38+(52-1)\times (-10)$

Hence, $a_{52}=-548$

(22)

$a_{n}=a_{n-1}-7$

$a_{1}=34$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-7$

Here $a_{1}=34$ and $d=-7$ .

Hence, $a_{52}=34+(52-1)\times (-7)$

Hence, $a_{52}=-323$

(23)

$a_{n}=a_{n-1}+10$

$a_{1}=37$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=10$

Here $a_{1}=37$ and $d=10$ .

Hence, $a_{52}=37+(52-1)\times (10)$

Hence, $a_{52}=547$

(24)

$a_{n}=a_{n-1}-100$

$a_{1}=-18$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-100$

Here $a_{1}=-18$ and $d=-100$ .

Hence, $a_{52}=-18+(52-1)\times (-100)$

Hence, $a_{52}=-5118$

5 0

4 years ago

sasha has a riddle: There are two numbers. The sum of the first number and twice the second number is 14.When the second number

N76 [4]

Answer: The first no. is 6 and the second no. is 4.

Step-by-step explanation: Let the 2 no. s be x and y respectively.

→x+ 2y = 14

→x-y = 2

∴ x = 2+y

y = y

∴ x+2y=14

= 2+y+2y=14

3y=14-2

3y=12 , y = 12/3=4

∴y = 4

→x = 2+y

= 2+4=6

∴x=6

Thus, the first no. is 6 and the second no. is 4.

5 0

3 years ago

What is the solution to this equation x - 12 = - 4

Alexandra [31]

Answer:

Step-by-step explanation:

x - 12 = -4 add 12 to both sides

x - 12 + 12 = -4 + 12

x = 8

3 0

4 years ago

Read 2 more answers

the segments ab and cd are graphed on a coordinate plane. The endpoints of ab are at (9,4) and (9,20). CD is parallel to the x-a

Step2247 [10]

Answer:

21, 8

Step-by-step explanation:

The second endpoint is of the form (X, 8) since it's parallel to the x axis.

Given the congruence of the two segments, we can tell that its length is 16 units (since $|4-20| = |-16|= 16$ )

At this point the two possible endpoints for the segment are $(5-16; 8)$ or $(5+16, 8)$ . The fact that the segment has to sit in the first quadrant rules out the first option (it's endpoint will be at (-11, 8) which will set most of it in the second quadrant) and we're left with (21, 8)

5 0

3 years ago