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erma4kov [3.2K]
3 years ago
6

What is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5m/s

Physics
1 answer:
Scrat [10]3 years ago
7 0

Answer:

203.1J

Explanation:

Given parameters:

Mass  = 65kg

Speed  = 2.5m/s

Unknown:

Kinetic energy of jogger  = ?

Solution:

To solve this problem, we use the kinetic energy equation:

    K.E  = \frac{1}{2} m v²  

m is the mass

v is the velocity

 Now insert  the parameters and solve;

  K.E  =  \frac{1}{2} x 65 x 2.5²   = 203.1J

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According to Newton's 2nd law of motion, if you hit a baseball with a bat it will _____.
shtirl [24]
Newton's second law says that the acceleration of an object is produced by the force exerted on it.
Having this in mind, if you hit a baseball with a bat it will <u>accelerate according to the applied force.</u>
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what is the percent efficiency of a light bulb that emits 14 joules of light for every 60 joules of electric energy thst enters
jasenka [17]
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3 years ago
How does distance from the equator affect the climate of an area?
AVprozaik [17]

Explanation :  

There are different factors that affect the climate of an area.The distance from the equator is one of them.

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6 0
3 years ago
A uniform, 4.5 kg, square, solid wooden gate 2.0 mm on each side hangs vertically from a frictionless pivot at the center of its
True [87]

Answer:

The angular velocity is  w = 1.43\  rad/sec

Explanation:

From the question we are told that

   The  mass of wooden gate  is m_g = 4.5 kg

    The  length of side is  L = 2 m

    The mass of the raven is  m_r = 1.2 kg

     The initial speed of the raven is u_r = 5.0m/s

     The final speed of the raven is   v_r = 1.5 m/s

From the law of  conservation of angular momentum we express this question mathematically as

       Total initial angular momentum  of both the Raven and  the Gate =  The Final angular momentum of both the Raven and the Gate  

The initial angular momentum of the Raven is m_r * u_r * \frac{L}{2}

Note: the length is half because the Raven hit the gate at the mid point

The initial angular momentum of the Gate is  zero

Note: This above is the generally formula for angular momentum of  square objects

  The final angular velocity  of the Raven is  m_r * v_r * \frac{L}{2}

   The  final angular velocity of the Gate  is   \frac{1}{3} m_g L^2 w

Substituting this formula

  m_r * u_r * \frac{L}{2}  =   \frac{1}{3} m_g L^2 w + m_r * v_r * \frac{L}{2}

  \frac{1}{3} m_g L^2 w   =    m_r * v_r * \frac{L}{2} -   m_r * u_r * \frac{L}{2}

  \frac{1}{3} m_g L^2 w   =    m_r *  \frac{L}{2} * [u_r - v_r]

Where w is the angular velocity

     Substituting value  

   \frac{1}{3} (4.5)(2)^2  w   =    1.2 *  \frac{2}{2} * [5 - 1.5]

     6w = 4.2

       w = \frac{6}{4.2}

            w = 1.43\  rad/sec

5 0
3 years ago
How many turns of wire are needed in a circular coil 13 cmcm in diameter to produce an induced emf of 5.6 VV
Artemon [7]

Answer:

Number of turns of wire(N) = 3,036 turns (Approx)

Explanation:

Given:

Diameter = 13 Cm

emf = 5.6 v

Note:

The given question is incomplete, unknown information is as follow.

Magnetic field increases = 0.25 T in 1.8 (Second)

Find:

Number of turns of wire(N)

Computation:

radius (r) = 13 / 2 = 6.5 cm = 0.065 m

Area = πr²

Area = (22/7)(0.065)(0.065)

Area = 0.013278 m²

So,

emf = (N)(A)(dB / dt)

5.6 = (N)(0.013278)(0.25 / 1.8)

5.6 = (N)(0.013278)(0.1389)

N = 3,036.35899

Number of turns of wire(N) = 3,036 turns (Approx)

7 0
3 years ago
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