Cryptologist is not a scientist.
Answer:

Explanation:
Given that,
Capacitance 1, 
Capacitance 2, 
Capacitance 3, 
C₁ and C₂ are connected in series. Their equivalent is given by :



Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :



So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.
F=mass times acceleration so multiple 50 by 1.5 and u get 75
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,

:

First we need to find the net charge flowing at a certain point of the wire in one second,

. Using I=0.92 A and re-arranging the previous equation, we find

Now we know that each electron carries a charge of

, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second: