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Paul [167]
3 years ago
14

The number density of gas atoms at a certain location in the space above our planet is about 1.05 × 1011 m-3, and the pressure i

s 2.7 × 10-10 Pa in this region.What is the temperature there?
Physics
1 answer:
Anettt [7]3 years ago
7 0

To solve this problem we will apply the concepts given by the ideal gas equation, which mathematically can be described as

PV = NkT

Here

P = Pressure

V = Volume

N = Number of atoms of molecules

k = Bolzmann constant

T = Temperature

Rearranging to find the temperature we have

T = \frac{PV}{Nk}

Since the value given in the exercise is a unit of atoms per volume, we will readjust the equation like this

T = \frac{P}{\frac{N}{V}k}

Replacing we have,

T = \frac{(2.7*10^{-10}N/m^2)}{(1.05*10^{11}/m^3)(1.38*10^{-23}J/K)}

T = 186.3K

T = -86.81\°C

Therefore the temperature is -86.81°C or 186.3K

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A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
kramer

Explanation:

The gravitational force equation is the following:

F_G = G * \frac{m_1 m_2}{r^2} \\

Where:

G = Gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

m1 & m2 = the mass of two related objects

r = distance between the two related objects

The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.

8 0
3 years ago
A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg,
xz_007 [3.2K]
I already answered this question. 
Please refer to this link brainly.com/question/8743596.
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3 years ago
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AveGali [126]

The best and most correct answer among the choices provided by your question is the fourth option or letter D. Trade winds blow towards the equator because t<span>he Equator receives the most heat energy.

</span>The surface air that flows from these subtropical high-pressure belts toward the Equator is deflected toward the west in both hemispheres by the Coriolis effect. These winds blow<span> predominantly from the northeast in the Northern Hemisphere and from the southeast in the Southern Hemisphere.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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Tamiku [17]

Answer:

A

Explanation:

7 0
3 years ago
Read 2 more answers
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