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Paul [167]
3 years ago
14

The number density of gas atoms at a certain location in the space above our planet is about 1.05 × 1011 m-3, and the pressure i

s 2.7 × 10-10 Pa in this region.What is the temperature there?
Physics
1 answer:
Anettt [7]3 years ago
7 0

To solve this problem we will apply the concepts given by the ideal gas equation, which mathematically can be described as

PV = NkT

Here

P = Pressure

V = Volume

N = Number of atoms of molecules

k = Bolzmann constant

T = Temperature

Rearranging to find the temperature we have

T = \frac{PV}{Nk}

Since the value given in the exercise is a unit of atoms per volume, we will readjust the equation like this

T = \frac{P}{\frac{N}{V}k}

Replacing we have,

T = \frac{(2.7*10^{-10}N/m^2)}{(1.05*10^{11}/m^3)(1.38*10^{-23}J/K)}

T = 186.3K

T = -86.81\°C

Therefore the temperature is -86.81°C or 186.3K

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How much heat is required to convert 2.55g of water at 28 degrees c to steam?
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There are two different processes here:
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If we plug the numbers into the equation, we find
Q_1 = (2.55 g)(4.18 J/g^{\circ}C)(72^{\circ}C)=767.4 J

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