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Paul [167]
3 years ago
14

The number density of gas atoms at a certain location in the space above our planet is about 1.05 × 1011 m-3, and the pressure i

s 2.7 × 10-10 Pa in this region.What is the temperature there?
Physics
1 answer:
Anettt [7]3 years ago
7 0

To solve this problem we will apply the concepts given by the ideal gas equation, which mathematically can be described as

PV = NkT

Here

P = Pressure

V = Volume

N = Number of atoms of molecules

k = Bolzmann constant

T = Temperature

Rearranging to find the temperature we have

T = \frac{PV}{Nk}

Since the value given in the exercise is a unit of atoms per volume, we will readjust the equation like this

T = \frac{P}{\frac{N}{V}k}

Replacing we have,

T = \frac{(2.7*10^{-10}N/m^2)}{(1.05*10^{11}/m^3)(1.38*10^{-23}J/K)}

T = 186.3K

T = -86.81\°C

Therefore the temperature is -86.81°C or 186.3K

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The diffusion rate for a solute is 4.0 x 10^-11 kg/s in a solvent- filled channel that has a cross-sectional area of 0.50 cm^2 a
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Answer:

s = 9.6\times 10^{-12}kg/s

Explanation:

Given:

Solute Diffusion rate  = 4.0 × 10⁻¹¹ kg/s

Area of cross-section = 0.50 cm²

Length of channel  =0.25 cm

Now for the new channel

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now equating the diffusion rate per unit volume for both the channels

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a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time
Evgen [1.6K]

Answer:

1.43 s

Explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

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a= g = 9.8 m/s^2 is the acceleration

since u=0, it can be rewritten as

S=\frac{1}{2}gt^2

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3 years ago
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