Uh so I'm no master at this subject, but all stuffs accelerate at 9.8 m/s squared. So you multiply the 9.8 and the 0.20 it's given for reasons unknown other than that's what I see in my notes... and that gives you 1.96 m/s squared.
As for B, I have no idea. I think you may multiply the 1.96 by 4. Tell me your thoughts and maybe we can work it out together
Answer:
0.947 rad or 54.27 degrees
Explanation:
Suppose the collision is elastic, meaning the momentum is preserved.
Before the collision and the second ball has no momentum
Right after the collision and the first bast ball has no momentum.
Therefore momentum of the first baseball has been transferred to the 2nd ball
After the collision, the second ball would gained kinetic energy, which then would be transferred to potential energy once it reaches its highest point:
By the law of energy conservation:
By law of energy conservation:
So at its highest point, the ball is 0.562 m from the lowest point. Since the ball is hanging on a 1.35 m string, we can calculate the vertical distance from there to the swinging point:
1.35 - 0.562 = 0.788 m
Finally, the angle that string makes with the vertical at the highest point is
The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.
The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.
The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.Let the common acceleration = a m/s^2
Man: <em>net force = T - f = m a = 50 a </em>
<em>net force = T - f = m a = 50 a </em>
<em>Plank: net force = T + f = m a = 100 a</em>
<em>net force = T - f = m a = 50 a </em>
<em>Plank: net force = T + f = m a = 100 a</em>
<em>As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons. </em>
[correct me if I'm wrong]:)
Answer:
0.12m/s
Explanation:
v=λf
Given that, λ = 12cm = 0.12m
T = 1second
(A period T is the time required for one complete cycle of vibration to pass a given point)
frequency 'f' is unknown but we can get frequency from f = 1/T = 1/1 = 1Hz
therefore, v= 0.12 × 1 = 0.12m/s