Answer:
number = 267
Step-by-step explanation:
i am a 3 digit number divisible by 3.
100a + 10b + c
my tens digit is 3 times as great as my hundreds digit
b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9
and the sum of my digits is 15.
a + b + c = 15
if you reverse my digits i am divisible by 6 and 3
100c + 10b + a
this is a logic problem, an equation won't help us here
From the given information b = 3a, and the sum of the 3 digits = 15, we have:
1 3 ___; three single digits can't add up to 15
2 6 _7_; this has to be the number
3 9 _3_; reverse number is not different
Check for division by 3 and 6
267/3 = 89
762/6 = 127
267 is the number
3^5
3 x 3 x 3
3:5 <- I think
Answer:
The graph of g is the graph of f shifted down 1 unit.
Step-by-step explanation:
Suppose you have a function y = f(x), you can do these following operations on the function:
Shift up a units: y = f(x) + a
Shift down a units: y = f(x) - a
Shift left a units: y = f(x + a)
Shift right a units: y = f(x - a)
In this problem, we have that:
g(x) = -1 + f(x) = f(x) - 1
So the graph of g is the graph of f shifted down 1 unit.
Nicoles pattern:
1
5
17
53
161
Ian’s pattern:
0
1
3
7
15
Ordered pair:
(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)
Table 1 -
Sequence 1:
9
11
13
15
17
Sequence 2:
5
8
11
14
17
Ordered pair:
(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)
Table 2 -
Sequence 1:
20
16
12
8
4
Sequence 2:
20
17
14
11
8
Ordered pair:
(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)
Table 3 -
Sequence 1:
1
3
7
15
31
Sequence 2:
40
24
16
12
10
Ordered pair:
(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)
Let's call the aces 
for hearts, diamonds, clubs and spades. So, 
are red and [ted] c, s[/tex] are black.
Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple
There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:
If we want a player to draw two card of the same colour, the following couples are good:
so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.
Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:
which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.
