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mariarad [96]
3 years ago
9

1. Find the missing side lengths of the special right triangles. Leave your answers as radicals in simplest form 30° 9​

Mathematics
1 answer:
juin [17]3 years ago
3 0

Answer:

a = 18 units

b = 9√3 units

Step-by-step explanation:

By applying sine rule in the given triangle,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{9}{a}

a = 18 units

Now apply cosine rule in the given triangle,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{\sqrt{3}}{2}=\frac{b}{a}

\frac{\sqrt{3}}{2}=\frac{b}{18}

b = \frac{18\sqrt{3} }{2}

b = 9\sqrt{3} units

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