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jenyasd209 [6]
4 years ago
15

How to separate milk and water​

Chemistry
1 answer:
ch4aika [34]4 years ago
7 0

Answer:

Milk is a mixture of protein and fat and sugars suspended in water. Water is mixed with milk in order to make it more dilute. Once the water is mixed with milk, it is not easy to separate the milk from water. What is possible is to concentrate the milk by evaporating a part of the water contained in milk

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a container with a volume of 3.46 liters contains a gas at a pressure of 1.30 atm and temperature of 274.27 kelvins how many mol
balu736 [363]
There are 0.19 ((1.3*3.46)/(0.082*274.27) moles of gas are in the container. This problem can be solved using the ideal gas law formula which stated as PV=nRT where P is the gas' pressure, v is the gas' volume, n is the gas' mole amount, R is the constant gas standard (0.082), and T is the gas' temperature<span>.</span>
8 0
3 years ago
Assume the alveolar radii are 0.05 and 0.07 mm towards the end of exhalation. Knowing that air flows from high to low pressures,
xeze [42]

Answer:

0.286 mN/m^2

Explanation:

Using Laplace's law of surface tension:

P=\frac{2T}{r}

where:

P = pressure

T = surface tension

r = radius

In the longer alveoli with radius of  0.07 mm = 0.07*10^{-2}m; we have:

P =  \frac{2*25mN/m}{0.07*10^{-2}m}

P = 0.714 mN/m^2

In the smaller alveoli with radius 0.05 mm = 0.05 * 10^{-2} m; we have:

P = \frac{2*25mN/m}{0.05*10^-2m}

P = 1.00 mN/m^2

The pressure difference can now be calculate as follows:

Pressure difference = (1.00 - 0.714)mN/m^2

Pressure difference = 0.286 mN/m^2

5 0
3 years ago
A scientist has 400 ml of an 8% solution. How much water needs to be added to reduce this to a 2% solution?
mr_godi [17]

Answer:

Explanation:30

7 0
4 years ago
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
slamgirl [31]
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
1.20 moles of Silicon are added to 1.00 moles of Nitrogen gas.
(5 Points) Balance the equation and indicate the phases.

Si (___) + N2 (___) → Si3N4 (___)

(5 Points) What is the limiting reactant? You must show your work.
4 0
3 years ago
How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor
Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions =  7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0
4 years ago
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