I don’t see what you need help with but thanks:)
Given:
P = 123 kPa
V = 10.0 L
n = 0.500 moles
T = ?
Assume that the gas ideally, thus, we can use the ideal gas equation:
PV = nRT
where R = 0.0821 L atm/mol K
123 kPa * 1 atm/101.325 kPa * 10.0 L = 0.500 moles * 0.0821 Latm/molK * T
solve for T
T = 295.72 K<span />
3.46 g Cu 1 mol Cu 6.02*10^23 atoms Cu =
63.55 g Cu 1 mol Cu
3.28*10^22 atoms Cu
Answer:
1. C = 0.73 M.
2. pH = 0.14
Explanation:
The reaction is the following:
HCl + NH₃ ⇄ NH₄⁺Cl⁻
From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

Where "a" is for acid and "b" is for base.
The number of moles is:
Where "C" is for concentration and "V" for volume.


Hence the initial concentration of the acid is 0.73 M.
The original pH of the acid is given by:
![pH = -log([H^{+}])](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%28%5BH%5E%7B%2B%7D%5D%29%20)
Therefore, the original pH of the acid is 0.14.
I hope it helps you!