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Aleonysh [2.5K]
3 years ago
9

Helium balloons stay the same size as you hold them, but swell and burst as they rise to high altitudes when you let them go. Wh

at are the forces on the inside of the balloon? What are the forces on the outside of the balloon?
Chemistry
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

Inside balloon outward normal force.

Outside balloon compressing atmospheric force.

Explanation:

At ground level gases outside and helium inside are in static equilibrium with balloon as separating surface. Both balloon and atmospheric forces are compressing to maintain that state.

But as balloon moves upward because of less density of helium gas in balloon internal force of helium gas increases. At high altitude atmospheric pressure decreases due to gravitational pull and fluid nature of gas. So equilibrium reestablish and it start to expand at high altitude.

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6.45 g of C6H12O6 is burned in a bomb calorimeter containing 950. g of water and the temperature goes from 35.0∘C to 42.3∘C. If
emmasim [6.3K]

Answer:

q_{rxn}=-488.86\frac{kJ}{mol}

Explanation:

Hello!

In this case, since this calorimetry problems can by analyzed by figuring out that the heat lost due to the combustion of C6H12O6 is gained by the water and the calorimeter which undergo the mentioned temperature rise, we can write:

Q_{rxn}=-(m_wC_w+C_c)(T_2-T_1)

Thus, by plugging in the given data, we obtain:

Q_{rxn}=-(950.0g*4.184\frac{J}{g\°C} +933\frac{J}{\°C})(42.3\°C-35.0\°C)\\\\Q_{rxn}=-17.5kJ

Next, we compute the moles of C6H12O6 by using its molar mass (180.18 g/mol) as shown below:

n=6.45g*\frac{1mol}{180.18g} =0.0358mol

Thus, the value for q of the reaction turns out:

q_{rxn}=\frac{Q_{rxn}}{n} \\\\q_{rxn}=\frac{17.5kJ}{0.0358mol} \\\\q_{rxn}=-488.86\frac{kJ}{mol}

Best regards!

8 0
3 years ago
Read 2 more answers
PLZ HELP FAST
astra-53 [7]
#1
The correct answer is A.)

Because the animal has sperm that means that the offspring will be different. This is because at conception, the two parents sex cells combine their DNA to make a new creature.

#2
The correct answer is B.)

Genetic variation produces different offspring, and some are more adapted to others. The ones that survive pass on their genes. This is know as "Survival of the Fittest". Asexually organisms are exactly like their parents, so if they have any type of genetic defaults, then their offspring will get them too. 

Hope this helps! 

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3 0
3 years ago
The compound sodium thiosulfate pentahydrate, Na2S2O3 • 5H2O
Mnenie [13.5K]

The theoretical yield is 204.4 g while the percent yield is 2.57%.

<h3>What is theoretical yield?</h3>

Theoretical yield is the amount of product obtained based on the stoichiometry of the reaction.

S8(s) + 8 Na2SO3(aq) + 40 H2O(l) --->8 Na2S2O3·5 H2O(s)

Number of moles of sulfur =  3.25 g /8(32) = 0.013 moles

Number of moles of sodium sulfite =  13.1 g/126 g/mol = 0.103 moles

Since 1 moles of sulfur reacts with 8 moles of sodium sulfite

0.013 moles reacts with 0.013 moles ×  8 moles /1 mole = 0.104 moles

There is not enough sodium sulfite hence it is the limiting reactant.

1 mole of sodium sulfite yields 8 moles of product

0.103 moles of sodium sulfite yields  0.103 moles × 8 moles /1 mole = 0.824 moles

Mass of product = 0.824 moles × 248 g/mol = 204.4 g

percent yield =  5.26 g /204.4 g × 100/1

= 2.57%

Learn more about percent yield: brainly.com/question/2506978

4 0
2 years ago
An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

Best regards!

5 0
3 years ago
How many particles are in 12.47 grams of NaCl?
jeka94
If we are talking about moles then the answer to that is 0.22
5 0
3 years ago
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