Work is calculated by multiplying force by the distance that the object had moved. The applied force is 60 N, moving the object by 10 m. Thus, the work does is 600 J. For the friction force which is equal to,
100N x 0.250 = 25.0 N
the work done is,
W = (60 N - 25 N) x 10 m = 350 J
The kinetic energy of the box can be equated to this force. Thus, the answer is also 350 J.
Answer:
Electric Current
Explanation:
The flow (or free movement) of these electrons through a wire.
Pretty sure :)
Answer:
375 m.
Explanation:
From the question,
Work done by the frictional force = Kinetic energy of the object
F×d = 1/2m(v²-u²)..................... Equation 1
Where F = Force of friction, d = distance it slide before coming to rest, m = mass of the object, u = initial speed of the object, v = final speed of the object.
Make d the subject of the equation.
d = 1/2m(v²-u²)/F.................. Equation 2
Given: m = 60.0 kg, v = 0 m/s(coming to rest), u = 25 m/s, F = -50 N.
Note: If is negative because it tends to oppose the motion of the object.
Substitute into equation 2
d = 1/2(60)(0²-25²)/-50
d = 30(-625)/-50
d = -18750/-50
d = 375 m.
Hence the it will slide before coming to rest = 375 m
Renewable resources naturally replenish themselves....and the is definitely true for trees
0.118 m is the distance between the two protons.
Mass of proton = 1.6726 × 10⁻²⁷ kg
Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N
= 1.6408 × 10⁻²⁶ N
Charge of proton = 1.602 × 10⁻²⁹ C
The force between two protons = kq²/r² where, K is a proportionality
constant, q is a charge of proton and
r is the distance between two protons.
= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
To calculate distance :
Weight of proton= Force between protons
⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
⇒ r = 0.118m
Therefore, 0.118 m is the distance between the two protons.
Learn more about electrostatic force here:
brainly.com/question/18108470
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