Answer:
The electric current in the wire is 0.8 A
Explanation:
We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:

B= Magnetic field due to a straight and long wire that carries current
u= Free space permeability
I= Electrical current passing through the wire
a = Perpendicular distance from the wire to the point where the magnetic field is located
Magnetic Field Calculation
We cleared (I) of the formula (1):
Formula(2)

a =8cm=0.08m

We replace the known information in the formula (2)

I=0.8 A
Answer: The electric current in the wire is 0.8 A
Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.
<h3>How is the aerobic breathing process?</h3>
Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.
In this case, Aerobic cellular respiration have 3 parts:
- Glycolysis(yeilds 2ATP & 2NADH).
- Pyruvate Oxidation(yeilds 2NADH).
- Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).
So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.
See more about Aerobic cellular respiration at brainly.com/question/22531444
#SPJ4
Exert force upward.
Like when you pick something up from the floor, or walk up the stairs.
Answer:
the correct answers are d, e, & f
Explanation:
just took the edge test
Answer:

Explanation:
Let the mass of copper ball is "m" gram
now the total number of copper atom present in the ball is given as

now the total number of electrons in one copper atom is 29
so total number of electrons in given sample of copper ball is

now diameter of the ball is 7.0 mm
density of the ball = 
now we have



now we have

now the charge on the copper ball is 40 nC
so the number of electrons removed



so the fraction of number of electrons removed is given as


