The diagram shows a sealed container, which
2 answers:
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Answer:
11m/s
Explanation:
Given parameters:
Mass of the lead shot = 8kg
Energy of the shot = 484J
Unknown:
Velocity of the shot = ?
Solution:
To solve this problem, we apply the kinetic energy formula;
K.E = m v²
m is the mass
v is the unknown
Now, insert the parameters and solve;
484 = x 8 x v²
484 = 4v²
v² = 121
v = 11m/s
Answer:
a.
b.
Explanation:
<u>Given:</u>
- Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .
The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.
At time t = 3 seconds,
<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>
<h2>(b):</h2>
The velocity of the particle at some is defined as the rate of change of the position of the particle.
For the time interval of 2 seconds,
The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,
It is the displacement of the particle in 2 seconds.