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4 years ago

Which is 20 miles per hour north an example of?

Physics

2 answers:

alina1380 [7]4 years ago

7 0

D. Velocity
This is because velocity is the speed of something in a specific way.

puteri [66]4 years ago

6 0

D. Velocity because it describes a speed and direction

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a motorcyclist starts from rest and accelerates at rate of 4 meters per second squared north. what is the final velocity of the

MArishka [77]

Answer:

80m/s

Explanation:

Final velocity is given by

v=u+at

when a motorcyclist starts from rest, initial velocity (u) =0

therefore

v=0+4*20

v=80m/s

that's the answer

8 0

4 years ago

How do the different forms of potential energy depend on an object's position or chemical composition?

devlian [24]

It depends on the objects chemical composition.

6 0

3 years ago

What are physics? How do you use physics on a daily basis?

Keith_Richards [23]

The physics is involved in many daily activities,

Forrxample,

1. At the time of wake up when the alarm clock rings, the sound from the alarm clock is studied by using physics, the angular motion of the pins on the clock.

2. The oscillation and time period of the minute, second and hour hand.

3. The tranformation of our energy from food to the energy for motion of our body.

4. The balance of our house equipments on the tab

4 0

1 year ago

An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a

devlian [24]

Answer:

$D = 1162.7 \ m$

$\beta =- 65.55^o$

Explanation:

From the question we are told that

The speed of the airplane is $u = 92.3 \ m/s$

The angle is $\theta = 51.1^o$

The altitude of the plane is $d = 532 \ m$

Generally the y-component of the airplanes velocity is

$u_y = v * sin (\theta )$

=> $u_y = 92.3 * sin ( 51.1 )$

=> $u_y = 71.83 \ m/s$

Generally the displacement traveled by the package in the vertical direction is

$d = (u_y)t + \frac{1}{2}(-g)t^2$

=> $-532 = 71.83 t + \frac{1}{2}(-9.8)t^2$

Here the negative sign for the distance show that the direction is along the negative y-axis

=> $4.9t^2 - 71.83t - 532 = 0$

Solving this using quadratic formula we obtain that

$t = 20.06 \ s$

Generally the x-component of the velocity is

$u_x = u * cos (\theta)$

=> $u_x = 92.3 * cos (51.1)$

=> $u_x = 57.96 \ m/s$

Generally the distance travel in the horizontal direction is

$D = u_x * t$

=> $D = 57.96 * 20.06$

=> $D = 1162.7 \ m$

Generally the angle of the velocity vector relative to the ground is mathematically represented as

$\beta = tan ^{-1}[\frac{v_y}{v_x } ]$

Here $v_y$ is the final velocity of the package along the vertical axis and this is mathematically represented as

$v_y = u_y - gt$

=> $v_y = 71.83 - 9.8 * 20.06$

=> $v_y = -130.05 \ m/s$

and v_x is the final velocity of the package which is equivalent to the initial velocity $u_x$

$\beta = tan ^{-1}[-130.05}{57.96 } ]$

$\beta =- 65.55^o$

The negative direction show that it is moving towards the south east direction

6 0

3 years ago

Suppose C⃗ =A⃗ +B⃗ where vector A⃗ has components Ax = 5, Ay = 2 and vector B⃗ has components Bx = -3, By = -5. What is the dire

Leto [7]

First, find the components of vector C (I don't know how you added the vector arrow but that's pretty cool).

Ax + Bx = Cx, Ay + By = Cy
5 + -3 = 2, 2 + -5 = -3

Vector C can be represented as 2x, -3y.

Next, using a trigonometric function tangent you may find the angle from the origin

$\theta$ = arctan(-3/2)

$\theta = -56.31$ ° $= -0.983$ rad

7 0

3 years ago

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