Electromagnetic force. It is where alike forces ( negative, negative & positive , positive) repel and opposite forces ( negative & positive ) attract.
Hopes this helped
Answer:
The average speed of the Earth in its orbit is 4.74 km/s.
Explanation:
Distance between the Earth and the Sun ,r= 149.60 million km = 
Considering the movement of Earth around the Sun follows circular path.
The circumference of circular path will be give by :

Time taken by Earth to complete revolution around earth ,T= 1 year
1 year = 365 days
1 year = 31,536,000 seconds
T = 31,536,000 seconds
Speed of the Earth around the Sun :S


The average speed of the Earth in its orbit is 4.74 km/s.
Answer:
y = 0.99 m
Explanation:
This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry
cos θ = v₀ₓ / v₀
sin θ = v_{oy} / v₀
v₀ₓ = vo cos θ
v_{oy} = I go sin θ
v₀ₓ = 15 cos 30 = 12.99 m / s
v_{oy} = 15 sin 30 = 7.5 m / s
Let's find the time it takes to travel x = 18 m
x = v₀ₓ t
t = x / v₀ₓ
t = 18 / 12.99
t = 1,385 s
at this point it is at a height of
y = v_{oy} - ½ g t²
y = 7.5 1.385 - ½ 9.8 1.385²
y = 0.99 m
therefore the camera must place the foot 99 cm from the ground
Answer:
F = 2074.13 lb
Explanation:
Given that,
Mass of car, m = 2800 lb = 1270.059 kg
Initial speed, u = 5 mi/h = 2.2352 m/s
Final speed, v = - 1.5 mi/h = -0.67056 m/s (in opposite direction)
Time, t = 0.4 s
We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

or
F = -2074.13 lb
So, the required force is 2074.13 lb.