Answer:
Explanation:
Given that,
Number of turns of coil
N = 50 turns
Initial area of plane
A1 = 0.18 m²
The coil it stretch to a no area in time t = 0.1s
No area implies that the final area is 0, A2 = 0 m²
Constant magnetic field strength
B = 1.51 T
EMF?
EMF is given as
Using far away Lenz law
ε = —N• dΦ/dt
Where Φ = BA
Then,
ε = —N• d(BA)/dt
Since B is constant,
ε = —N•B dA/dt
ε = —N•B (∆A/∆t)
ε = —N•B(A2—A1)/(t2-t1)
ε = —50 × 1.51 (0—0.18)/(0.1—0)
ε =—75.5 × —0.18 / 0.1
ε = 135.9 V
The induced EMF is 135.9V
Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Since the area lines in the plane, then the induced emf will be out of the page
Answer:
** incident ray.
Incident ray - the ray of light falling on the surface AB is called the incident ray
reflected ray.
** Reflected ray - the incident ray bouncing back in the same medium after striking the reflecting surface is called reflected ray.
Answer:
B. over the symbol.
Explanation:
vectors are represented with a symbol carrying an arrow head with also indicates direction
Answer:
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
Explanation:
We know the object with the most potential energy and this is the object at C.
Potential energy is the energy due to the position of a body above the ground surface.
The higher a body is above ground, the more its potential energy.
Potential energy = mass x acceleration due to gravity x height
So;
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
This is because, the height and mass of the objects are not quantified using numbers.
Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.
Answer:
Explanation:
As we know that initial and final speed of the beam is zero
so we can use energy conservation here to find the applied force
So we will have
work done by all the forces = change in kinetic energy of the beam
so we will have
so we will have
