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2 years ago

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A revolutionary war cannon, with a mass of 2240 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 131 m/s aft

er it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired?Answer in units of m/s.

1 answer:

My name is Ann [436]2 years ago

8 0

Answer:

v' = -0.0906 m/s

Explanation:

given,

mass of cannon, M = 2240 Kg

mass of the ball, m = 15.5 Kg

speed of cannon ball, v = 131 m/s

speed of he cannon = ?

initial speed of cannon and the cannon ball is equal to 0 m/s

using conservation of energy

(M+m)V = M v' + m v

(M+m) x 0= 22400 v' + 15.5 x 131

22400 v' = -2030.5

v' = -0.0906 m/s

negative sign represent the canon will move in opposite direction of the ball.

hence, speed of cannon is equal to 0.0906 m/s

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b)

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Answer:

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We know that

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1 × $\sin 56.6$ = $n_{violet}$ × $\sin 36.4$

$n_{violet}$ = 1.406

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$n = \frac{c}{v}$

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$v_{red} = \frac{c}{n_{red} }$

$v_{red} = \frac{3(10^{8} )}{1.344}$

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This is the velocity of red light in the glass.

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$v_{violet} = \frac{3(10^{8} )}{1.406}$

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2 years ago

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shusha [124]

Answer:

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Explanation:

Given:

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- One on y-axis

- All three charges are vertices

Find:

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- Show that the working reduces to point charge when y >> a.

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3 years ago