A revolutionary war cannon, with a mass of 2240 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 131 m/s aft
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<h2>Hello!</h2>
The answer is: 201 J of kinetic energy.
<h2>Why?</h2>The motion of a pendulum (with no friction considered) is a continuous exchange between potential energy and kinetic energy.
So, at the highest point of its swing, the potential energy will be the maximum potential energy that the pendulum can have and the kinetic energy will be 0 since at max height the speed tends to 0.
On the opposite side, when the pendulum is at the bottom (the lowest point of its swing) the potential energy will be the minimum (tends to 0) but the kinetic energy will be the maximum.
Also, in the pendulum motion, the total energy is conserved, meaning that:
Where,
PE(h),is the potential energy at the highest point.
KE(h), is the kinetic energy at the highest point.
PE(l), is the potential energy at the lowest point (bottom of pendulum swing).
KE(l), is the kinetic energy at the lowest point (bottom of pendulum swing).
m, is the mass of the object.
g, is the acceleration of gravity.
v, is the speed of the object.
So, what is the energy at the bottom of its swing?
So, the pendulum has 201 of kinetic energy at the bottom of its swing.
Meaning that the energy is conserved.
Have a nice day!
Answer:
The overall velocity of the water when it hits the bottom is:
Explanation:
Use the law of conservation of energy.
Call it instant [1] to the moment when the water is just before reaching the falls.
At this moment its height h is 206 meters and its velocity horizontally is
m/s.
At the instant [1] the water has gravitational power energy
The water also has kinetic energy Ek.
Then the Total E1 energy is:
In the instant [2] the water is within an instant of touching the ground. At this point it only has kinetic energy, since the height h = 0. However at time [2] the water has maximum final velocity
So:
As the energy is conserved then
Now we solve for .