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enyata [817]
3 years ago
5

A revolutionary war cannon, with a mass of 2240 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 131 m/s aft

er it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired?Answer in units of m/s.
Physics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

v' = -0.0906 m/s

Explanation:

given,

mass of cannon, M = 2240 Kg

mass of the ball, m = 15.5 Kg

speed of cannon ball, v = 131 m/s

speed of he cannon = ?

initial speed of cannon and the cannon ball is equal to 0 m/s

using conservation of energy

(M+m)V = M v' + m v

(M+m) x 0= 22400 v' + 15.5 x 131

22400 v' = -2030.5

v' = -0.0906 m/s

negative sign represent the canon will move in opposite direction of the ball.

hence, speed of cannon is equal to 0.0906 m/s

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Electromagnetic force. It is where alike forces ( negative, negative & positive , positive) repel and opposite forces ( negative & positive ) attract.
Hopes this helped
7 0
3 years ago
Determine the average distance between the Earth and the Sun. Then calculate the average speed of the Earth in its orbit in kilo
FrozenT [24]

Answer:

The average speed of the Earth in its orbit is 4.74 km/s.

Explanation:

Distance between the Earth and the Sun ,r= 149.60 million km = 149.60\times 10^6 km

Considering the movement of Earth  around the Sun follows circular path.

The circumference of circular path will be give by :

D=2\pi r=2\times 3.14\times 149.60\times 10^6 km

Time taken by Earth to complete revolution around earth ,T= 1 year

1 year = 365 days

1 year = 31,536,000 seconds

T = 31,536,000 seconds

Speed of the Earth around the Sun :S

S=\frac{D}{T}=\frac{149.60\times 10^6 km}{31,536,000 s}

S=4.74 km/s

The average speed of the Earth in its orbit is 4.74 km/s.

8 0
3 years ago
Mario golpea el balón con el pie para lanzárselo a Tamara que está situada a 18 m de distancia. El ángulo de salida del balón es
Brilliant_brown [7]

Answer:

y = 0.99 m

Explanation:

This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry

         cos θ = v₀ₓ / v₀

         sin θ = v_{oy} / v₀

         v₀ₓ = vo cos θ

         v_{oy} = I go sin θ

         v₀ₓ = 15 cos 30 = 12.99 m / s

         v_{oy} = 15 sin 30 = 7.5 m / s

Let's find the time it takes to travel x = 18 m

         x = v₀ₓ t

         t = x / v₀ₓ

         t = 18 / 12.99

         t = 1,385 s

at this point it is at a height of

         y = v_{oy} - ½ g t²

         y = 7.5 1.385 - ½ 9.8 1.385²

         y = 0.99 m

therefore the camera must place the foot 99 cm from the ground

7 0
3 years ago
In a test of an energy-absorbing bumper, a 2800-lb car is driven into a barrier at 5 mi/h. The duration of the impact is 0.4 sec
Fiesta28 [93]

Answer:

F = 2074.13 lb

Explanation:

Given that,

Mass of car, m = 2800 lb = 1270.059 kg

Initial speed, u = 5 mi/h = 2.2352 m/s

Final speed, v = - 1.5 mi/h = -0.67056 m/s  (in opposite direction)

Time, t = 0.4 s

We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

F=m\times \dfrac{v-u}{t}\\\\F=1270.059\times \dfrac{-0.67056 -2.2352 }{0.4}\\\\F=9226.21\ N

or

F = -2074.13 lb

So, the required force is 2074.13 lb.

5 0
3 years ago
A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic f
Lostsunrise [7]

Answer:

1.379 x 10^{-3} T. and into the page.

Explanation:

Download pdf
3 0
3 years ago
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