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Dafna11 [192]
3 years ago
13

A 100-kg athlete is performing a vertical leap to test his leg strength. He leaves the ground at 3.20 m/s, zooms upward to some

maximum altitude, and then returns to the ground. As he lands, he bends his legs and crouches down, so that he moves 30 cm downward as he comes to a stop. What average force did the athlete’s legs exert on the ground as he landed?
Physics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

2687.7 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

When he will reach the ground his speed will be 3.2 m/s but will travel 30 cm down

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.2^2}{2\times 0.3}\\\Rightarrow a=-17.067\ m/s^2

Force

F=m(g-a)\\\Rightarrow F=100\times (9.81-(-17.067))\\\Rightarrow F=2687.7\ N

The force on the legs will be 2687.7 N

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My believe the answer is

A.) or B.)

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Here is why I think A is the answer.

If we use the process of elimination, it would look like this,

a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.

<em>This makes sense because we all know in winter the weather is very cold and freezing.</em>

b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.

<em>I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.</em>

c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.

<em>This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.</em>

d) Porque la temperatura del aire es igual a la temperatura del cuerpo.

<em>This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.</em>

<em />

<em />

<h2>Well, have a nice rest of the day!</h2><h3>ba baiii!</h3>
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